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Aleksandr [31]
4 years ago
9

If you can not see clearly 100 ft in both directions when approaching an uncontrolled intersection, what should your rate of spe

ed be?
Physics
1 answer:
Lisa [10]4 years ago
7 0

Answer:

15 MPH or less than that

Explanation:

You shouldn't drive faster than 15 MPH so if a truck unexpectedly pulls out you'll have time to stop.

When parked cars, branches of the tree, fences, houses, or other things block your vision of an open intersection, you can pause before approaching the junction and move slowly ahead until you can see if there is cross-traffic before moving through the junction.

You might be interested in
Which states of a hydrogen atom can be excited by a collision with an electron with kinetic energy k = 12. 5 ev?
Sophie [7]

The answer is the  excited state of the hydrogen atom, n=24 and Z=23

Kinetic energy of electron is, $\mathrm{KE}=\frac{13.6 \mathrm{Z}^{2}}{\mathrm{n}^{2}} \mathrm{eV}$

For  the  excited state of the hydrogen atom , n=24 and Z=23

K.E=\frac{13.6 \times 23^{2}}{24^{2}}=12.5

What is the hydrogen atom?

  • The hydrogen atom is the most basic of all the atoms since it just has one proton and one electron.
  • There are two more hydrogen isotopes, deuterium and tritium, in addition to protium, which is the most prevalent form of the atom.
  • The hydrogen atom consists of a proton and an electron, and has a spherical symmetry that can most easily be studied using a spherical polar coordinate frame.

To learn more about hydrogen atom  visit: brainly.com/question/1462347?

#SPJ4

5 0
2 years ago
How long does it take a man to travel 6 km if his speed is 3km/h?
Ymorist [56]

why did my answer get deleted??

oh yeah i put a link on there- oopsies.

I wont this time!

I got 30!

3 0
2 years ago
The Bernoulli equation is valid for steady, inviscid, incompressible flows with a constant acceleration of gravity. Consider flo
irina1246 [14]

Answer:

p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

Explanation:

first write the newtons second law:

F_{s}=δma_{s}

Applying bernoulli,s equation as follows:

∑δp+\frac{1}{2} ρδV^{2} +δγz=0\\

Where, δp is the pressure change across the streamline and V is the fluid particle velocity

substitute ρg for {tex]γ[/tex] and g_{0}-cz for g

dp+d(\frac{1}{2}V^{2}+ρ(g_{0}-cz)dz=0

integrating the above equation using limits 1 and 2.

\int\limits^2_1  \, dp +\int\limits^2_1 {(\frac{1}{2}ρV^{2} )} \, +ρ \int\limits^2_1 {(g_{0}-cz )} \,dz=0\\p_{1}^{2}+\frac{1}{2}ρ(V^{2})_{1}^{2}+ρg_{0}z_{1}^{2}-ρc(\frac{z^{2}}{2})_{1}^{2}=0\\p_{2}-p_{1}+\frac{1}{2}ρ(V^{2}_{2}-V^{2}_{1})+ρg_{0}(z_{2}-z_{1})-\frac{1}{2}ρc(z^{2}_{2}-z^{2}_{1})=0\\p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

there the bernoulli equation for this flow is p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

note: ρ=density(ρ) in some parts and change(δ) in other parts of this equation. it just doesn't show up as that in formular

4 0
3 years ago
a) The student hypothesizes that a greater fraction of kinetic energy is lost from the system during the collision when the spee
Mashcka [7]

Answer with Explanation:

One hypothesis above would probably rely on the situation called <em>"inelastic collision." </em>The two carts are travelling towards each other at different speed. So, this means that once they collide, the kinetic energy will not be conserved but will be transferred as <em>sound energy, thermal energy or material deformation</em>. The impact will be great, thus a <u>greater fraction of kinetic energy will be lost from the system.</u>

6 0
3 years ago
A mass of 0.40 kg, hanging from a spring with a spring constant of 80 N/m, is set into an up-and-down simple harmonic motion. Wh
borishaifa [10]

Answer:

v = 1.22 m/s

Explanation:

Given that, Mass of the object, m = 0.4 kg

Spring constant of the spring, k = 80 N/m

The starting displacement from equilibrium is 0.10 m, or the amplitude, A = 0.1 m

To find, The speed of the mass when moving through the equilibrium point.

Displacement in the mass, y = 0.05

Solution, Let  is the angular frequency of the mass. It can be calculated as :

When the mass displaces from some position, the speed of the mass is given by : v = 1.22 m/s

So, the speed of the mass when moving through the equilibrium point is 1.22 m/s.

7 0
3 years ago
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