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3 years ago

A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?

Physics

1 answer:

MakcuM [25]3 years ago

3 0

Answer:

It will become a temporary magnet because the domains will easily realign.

Explanation:

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Why is the cathode ray oscilloscope evacuated?

Stels [109]

Answer:

please like

Explanation:

hope it helps you

7 0

3 years ago

A 70 pF capacitor and a 280 pF capacitor are both charged to 3.6 kV. They are then disconnected from the voltage source and are

e-lub [12.9K]

Answer:

0.636 kJ

Explanation:

The charge on any capacity, q = CV, thus,

The initial charge on the 70 pF capacitor is

q = Cv

q = 70*10^-12 * 3.6*10^3

q = 2.52*10^-7 C

The charge on the 280 pF capacitor is q = C*v

q = 280*10^-12 * 3.6*10^3

q = 1.008x10^-6 C

When they are connected as stated, the net total charge remaining will be 1.008*10^-6 - 2.52*10^-7 = 7.56*10^-7 C

Since the capacitors are in parallel, the equivalent capacitance will be 70 + 280 pF = 350 pF

Remember, q = CV, then V = q/C

V = 7.56*10^-7 C / 350*10^12 F

V = 2160 V

b) The energy before is 1/2 C*v²

E = 1/2 * 70*10^-12 * 3600² + 1/2 * 280*10^-12 * 3600²

E = 4.536*10^-4 J + 1.814*10^-3 J

E = 2.268 kJ

The energy After is 1/2 Cv²

E = 1/2 * 70*10^-12 * 2160² + 1/2 * 280*10^-12 * 2160²

E = 3.266*10^-4 J + 1.306*10^-3 J

E = 1.632 kJ

so the loss is 2.268 - 1.632 = 0.636 kJ

6 0

3 years ago

Please help I’ll give brainliest

marta [7]

Answer:

Repel

Unlike

Atrract

Fur

Balloon

Positivley charged

negative

postive

neutral

Explanation:

It goes from top to bottom

7 0

3 years ago

Find the mass of a child who runs at a speed of 4 m/s to get a pizza with extra cheese. His momentum is 120 kg•m/s.

tamaranim1 [39]

Wow! Very simple. Use the equation for momentum which is p=mv. You know your momentum and velocity, so do 120=m(4), now solve for m, which is 30. The mass of the child is 30 kg

7 0

3 years ago

A 10.0-kg box is pulled by a horizontal wire in a circle on a rough horizontal surface for which the coefficient of kinetic fric

QveST [7]

Answer:

a) $W_{f}=307.87 J$

b) $W_{f}=615.752 J$

c) Therefore it is a nonconservative force

Explanation:

Distance traveled in one complete circular trip against friction

$d=2\pi *r$

The force of friction is

$F_{f}=u*F_{N}$

$F_{N}=w*g$

The work of friction is the force of friction in the distance so

$W_{f}=-F_{f}*d$

a).

$F_{N}=10kg*9.8\frac{m}{s^2}$

$F_{N}=98N$

$F_{f}=0.250*98N$

$F_{f}=24.5N$

$W_{f}=-24.5N*2\pi*2m$

$W_{f}=307.87 J$

b).

$W_{f}=-24.5N*2\pi*4m$

$W_{f}=615.752 J$

c).

Since the circle returns to its initial position in both cases and the work done by the friction force different in both cases, so the friction force does depend on the path;

3 0

3 years ago