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2 years ago

A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?

Physics

1 answer:

MakcuM [25]2 years ago

3 0

Answer:

It will become a temporary magnet because the domains will easily realign.

Explanation:

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An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2010 × 103 seconds (about

vazorg [7]

Answer:

Radial acceleration of moon is $a_{r} = 2.246\times 10^{-3}$ $\frac{m}{s^{2} }$

Explanation:

Given :

Time period $T = 1.987 \times 10^{6}$ sec

Distance from center of moon to planet $r = 225 \times 10^{6}$ m

From the equation of radial acceleration,

$a_{r} = r\omega ^{2}$

Where $\omega = 2\pi f = \frac{2\pi }{T}$

So $\omega = 3.16 \times 10^{-6} \frac{rad}{s}$

Now moon's radial acceleration,

$a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}$

$a_{r} = 2246.76 \times 10^{-6}$

$a_{r} = 2.246\times 10^{-3}$ $\frac{m}{s^{2} }$

7 0

2 years ago

What is an example of vaporization?

Alenkasestr [34]

Answer:

just search it up you'll get ur answer

7 0

2 years ago

Read 2 more answers

F a forklift raises a 76-kg load a distance of 2.5 m, about how much work has it done?

sleet_krkn [62]

W= FxD. Since the weight is not put into force you’re going to convert it by multiplying it by 9.8 (gravity). 76kg x 9.8 = 7448. Then multiply that by the distance (2.5). Your answer is 1862.

6 0

3 years ago

An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled duri

Orlov [11]

Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is $13m/s^2$ .

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

$s=ut+\frac{1}{2}at^2$

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

$s=0\times5+\frac{1}{2}\times13\times 5^2$

$s=0+\frac{1}{2}\times13\times 25$

$s=0+\frac{1}{2}\times325$

s = 162.5 m

Therefore, distance traveled is 162.5 m.

3 0

3 years ago

A bridge spanning a river is 98.0 meters above the water.

svetlana [45]

Yes that ya 56.4 because dropped bridge to hit the water

7 0

2 years ago