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satela [25.4K]
2 years ago
13

Calculate how many grams of water needed to dissolve 35.00g KNO, at 50.0°C

Chemistry
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:use of significant figures in calculations in Essential Skills 1 () prior to working this example. A Density is mass per unit volume and is usually reported in grams per cubic understand its identity, he found that carbon dioxide dissolved in water to produce compounds were not generally accepted for more than 50 years.

Explanation:

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The number of electrons in outer ring for cesium
Degger [83]
The number of electrons in outer ring for cesium would be ONE 1.
5 0
2 years ago
Given the reaction 2NO2 1/202 N2O5, what is the relationship between the rates of formation of N,0, and disappearance of the two
daser333 [38]

Answer:

r=\frac{r(NO_{2})}{2} =\frac{r(O_{2})}{1/2}=\frac{r(N_{2}O_{5})}{1}

Explanation:

Let us consider the reaction:

2 NO₂ + 1/2 O₂ ⇄ N₂O₅

The rate of formation of a substance is equal to the change in concentration of the product divided the change in time:

r(N_{2}O_{5})=\frac{\Delta [N_{2}O_{5}] }{\Delta t}

The rate of disappearance of a reactant is equal to to the change in concentration of the reactant divided the change in time, with a negative sign so that the rate is always a positive variable.

r(NO_{2})=-\frac{\Delta[NO_{2}] }{\Delta t}

r(O_{2})=-\frac{\Delta[O_{2}] }{\Delta t}

The rate of the reaction is equal to the rate of any substance divided its stoichiometric coefficient. In this way, we can relate these expressions:

r=\frac{r(NO_{2})}{2} =\frac{r(O_{2})}{1/2}=\frac{r(N_{2}O_{5})}{1}

8 0
3 years ago
Which element has the lowest ionization energy?
UNO [17]
C the answer is cesium, study's show that it has the lowest ionization out of all elements. Hope this helped!
4 0
3 years ago
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21-B. Mn was used as an internal standard for measuring Fe by atomic absorption. A standard mixture containing 2.00 mg Mn/mL and
Korvikt [17]

Answer:

0.0693M Fe

Explanation:

It is possible to quantify Fe in a sample using Mn as internal standard using response factor formula:

F = A(analyte)×C(std) / A(std)×C(analyte) <em>(1)</em>

Where A is area of analyte and std, and C is concentration.

Replacing with first values:

F = 1.05×2.00mg/mL / 1.00×2.50mg/mL

<em>F = 0.84</em>

In the unknown solution, concentration of Mn is:

13.5mg/mL × (1.00mL/6.00mL) = <em>2.25 mg Mn/mL</em>

Replacing in (1) with absorbances values and F value:

0.84 = 0.185×2.25mg/mL / 0.128×C(analyte)

C(analyte) = <em>3.87 mg Fe / mL</em>

As molarity is moles of solute (Fe) per liter of solution:

\frac{3.87 mg Fe}{mL} \frac{1g}{1000mg} \frac{1mol}{55.845g} \frac{1000mL}{1L} = <em>0.0693M Fe</em>

7 0
3 years ago
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A ball is rolled at a velocity of 3 m/s and rolls for 5 seconds. How far does<br> the ball roll? *
MrRa [10]

Answer 15m

Explanation: Distance =  Speed x Time

3 x 5 =15

6 0
2 years ago
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