The number of electrons in outer ring for cesium would be ONE 1.
Answer:

Explanation:
Let us consider the reaction:
2 NO₂ + 1/2 O₂ ⇄ N₂O₅
The rate of formation of a substance is equal to the change in concentration of the product divided the change in time:
![r(N_{2}O_{5})=\frac{\Delta [N_{2}O_{5}] }{\Delta t}](https://tex.z-dn.net/?f=r%28N_%7B2%7DO_%7B5%7D%29%3D%5Cfrac%7B%5CDelta%20%5BN_%7B2%7DO_%7B5%7D%5D%20%7D%7B%5CDelta%20t%7D)
The rate of disappearance of a reactant is equal to to the change in concentration of the reactant divided the change in time, with a negative sign so that the rate is always a positive variable.
![r(NO_{2})=-\frac{\Delta[NO_{2}] }{\Delta t}](https://tex.z-dn.net/?f=r%28NO_%7B2%7D%29%3D-%5Cfrac%7B%5CDelta%5BNO_%7B2%7D%5D%20%7D%7B%5CDelta%20t%7D)
![r(O_{2})=-\frac{\Delta[O_{2}] }{\Delta t}](https://tex.z-dn.net/?f=r%28O_%7B2%7D%29%3D-%5Cfrac%7B%5CDelta%5BO_%7B2%7D%5D%20%7D%7B%5CDelta%20t%7D)
The rate of the reaction is equal to the rate of any substance divided its stoichiometric coefficient. In this way, we can relate these expressions:

C the answer is cesium, study's show that it has the lowest ionization out of all elements. Hope this helped!
Answer:
0.0693M Fe
Explanation:
It is possible to quantify Fe in a sample using Mn as internal standard using response factor formula:
F = A(analyte)×C(std) / A(std)×C(analyte) <em>(1)</em>
Where A is area of analyte and std, and C is concentration.
Replacing with first values:
F = 1.05×2.00mg/mL / 1.00×2.50mg/mL
<em>F = 0.84</em>
In the unknown solution, concentration of Mn is:
13.5mg/mL × (1.00mL/6.00mL) = <em>2.25 mg Mn/mL</em>
Replacing in (1) with absorbances values and F value:
0.84 = 0.185×2.25mg/mL / 0.128×C(analyte)
C(analyte) = <em>3.87 mg Fe / mL</em>
As molarity is moles of solute (Fe) per liter of solution:
= <em>0.0693M Fe</em>
Answer 15m
Explanation: Distance = Speed x Time
3 x 5 =15