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3 years ago

What does d in organic chemistry stand for

1 answer:

Nadusha1986 [10]3 years ago

6 0

<span> i think it's deuterium, the isotope of hydrogen that has a single neutron as well as a proton in the nucleus. As such, it has the same atomic number as hydrogen, which means you break the tie on atomic mass -- deuterium is higher priority than hydrogen but lower than everything else.
hoped it helped !!!
</span>

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A tire is filled to a gauge pressure of 2 atm at 27 degrees Celsius after a drive the temperature within the tire rises to 47 de

Ivenika [448]

Answer:

2.13atm

Explanation:

The following information were obtained from the question:

P1 (initial pressure) = 2atm

T1 (initial temperature) = 27°C = 27 + 273 = 300K

T2 (final temperature) = 47°C = 47 + 273 = 320K

P2 (final pressure) =?

Using the equation P1/T1 = P2/T2, the final pressure within the tyre can be obtained as illustrated below:

P1/T1 = P2/T2

2/300 = P2/320

Cross multiply to express in linear form

300 x P2 = 2 x 320

Divide both side by 300

P2 = (2 x 320)/300

P2 = 2.13atm

Therefore, the pressure within the tyre at 47°C is 2.13atm

4 0

3 years ago

At a pressure of 125 atm, a sample of a gas has a volume of 150 L. What pressure does it have when the gas is compressed to 40 L

zepelin [54]

Answer:

???

Explanation:

I have no clue sorry

6 0

3 years ago

CHEM ASSIGNMENT!!<br><br> PLEASE HELP

bogdanovich [222]

Answer:

Explanation:

q=mcat

q= 50g(4.184)(100-100)

q = 0

4 0

3 years ago

In the first step of the Ostwald process for the synthesis of nitric acid, ammonia is converted to nitric oxide by the high-temp

Paul [167]

Solution: The given balanced equation is:

$4NH_3+5O_2\rightarrow 4NO+6H_2O$

If we have a hypothetical equation:

$A+2B\rightarrow 3C+5D$

Then the rate could be written as:

$rate=-\frac{\Delta [A]}{\Delta t}=-\frac{1}{2}\frac{\Delta [B]}{\Delta t}=\frac{1}{3}\frac{\Delta [C]}{\Delta t}=\frac{1}{5}\frac{\Delta [D]}{\Delta t}$

From above expression one thing could easily be noticed that the coefficients of all are inverted. Also, there is negative sign in front of reactants and positive sign in front of the products. Negative sign stands for rate of consumption where as positive sign stands for rate of formation.

Like the above example, we can write the rate for the given equation and it would be looking as:

$rate=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}=-\frac{1}{5}\frac{\Delta [O_2]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO]}{\Delta t}=\frac{1}{6}\frac{\Delta [H_2O]}{\Delta t}$

Now we can easily answer all the parts of the question.

(a) From above expression, the rate of consumption of $O_2$ related to rate of consumption of $NH_3$ as:

$-\frac{1}{5}\frac{\Delta [O_2]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

multiply both sides by -5

$\frac{\Delta [O_2]}{\Delta t}=\frac{5}{4}\frac{\Delta [NH_3]}{\Delta t}$

So, rate of consumption of oxygen is $\frac{5}{4}$ the rate of consumption of ammonia.

(b) The relationship between rate of formation of NO to the rate of consumption of ammonia will be written as:

$\frac{1}{4}\frac{\Delta [NO]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

Multiply both sides by 4

$\frac{\Delta [NO]}{\Delta t}=-\frac{\Delta [NH_3]}{\Delta t}$

So, rate of formation of NO equals to the rate of consumption of ammonia.

Now, the rate of formation of $H_2O$ to the rate of consumption of ammonia would be:

$\frac{1}{6}\frac{\Delta [H_2O]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

Multiply both sides by 6

$\frac{\Delta [H_2O]}{\Delta t}=-\frac{6}{4}\frac{\Delta [NH_3]}{\Delta t}$

So, the rate of formation of $H_2O$ is $\frac{6}{4}$ times that is 1.5 times to the rate of consumption of ammonia.

5 0

4 years ago

What is the mole ratio of iron (III) chloride (FeCl3) to zinc chloride (ZnCl2) ?

tatiyna

Answer:C

Explanation:

4 0

3 years ago