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bagirrra123 [75]
3 years ago
14

What does d in organic chemistry stand for

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
6 0
<span>  i think it's deuterium, the isotope of hydrogen that has a single neutron as well as a proton in the nucleus. As such, it has the same atomic number as hydrogen, which means you break the tie on atomic mass -- deuterium is higher priority than hydrogen but lower than everything else.
hoped it helped !!!
</span>
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3 What is the number located in the top right hand corner of the atomic symbol of an ion with 16 protons, 17 neutrons and 14 ele
siniylev [52]

The number located in the top right corner of the ion is +2

An ion is an atom or group of atoms which possess an electric charge.

The charge on an ion can be obtained by using the following formula:

<h3>Charge = Proton – Electron </h3>

With the above formula, we can obtain the charge of the ion given in the question above as illustrated below:

Proton = 16

Neutron = 17

Electron = 14

<h3>Charge =? </h3>

Charge = Proton – Electron

Charge = 16 – 14

<h3>Charge = +2</h3>

Therefore, the charge on the ion is +2

Learn more: brainly.com/question/3428265

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larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

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