Answer:
549.48 mmHg
Explanation:
We'll begin by calculating the number of mole of oxygen in 4 g. This can be obtained as follow:
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ = 4 g
Mole of O₂ =?
Mole = mass /molar mass
Mole of O₂ = 4/32
Mole of O₂ = 0.125 mole
Next, we shall convert 37.0 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T (°C) = 37.0 °C
T(K) = 37.0 °C + 273
T(K) = 310 K
Next, we shall convert 4400 mL to L.
1000 mL = 1 L
Therefore,
4400 mL = 4400 mL × 1 L / 1000 mL
4400 mL = 4.4 L
Next, we shall determine the pressure. This can be obtained as follow:
Number of mole (n) = 0.125 mole
Temperature (T) = 310 K
Volume (V) = 4.4 L
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 4.4 = 0.125 × 0.0821 × 310
Divide both side by 4.4
P = (0.125 × 0.0821 × 310) / 4.4
P = 0.723 atm
Finally, we shall convert 0.723 atm to mmHg.
1 atm = 760 mmHg
Therefore,
0.723 atm = 0.723 atm × 760 mmHg / 1 atm
0.723 atm = 549.48 mmHg
Thus, the pressure is 549.48 mmHg
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