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uysha [10]
3 years ago
10

The rate constant (k) for a reaction was measured as a function of temperature. a plot of lnk versus 1/t(in k) is linear and has

a slope of −9.20×103 k . you may want to reference (pages 642 - 648) section 14.5 while completing this problem. part a calculate the activation energy for the reaction.
Chemistry
1 answer:
NNADVOKAT [17]3 years ago
7 0

The Arrhenius equation is

K=Ae^-{\frac{Ea}{RT}}

so if we plot a graph between lnK (natural log of rate constant) and 1/T (inverse of temperature in kelvin)

The straight line equation will be

lnK = lnA - Ea/RT

Where

A = constant for a particular reaction at any temperature

R = gas constant = 8.314 J /molK

So as per this equation the slope of line will be = -Ea/R

Or

Ea = -slope X R

Ea = -(-9.20X10³X 8.314) =76.49kJ /mol

Answer: activation energy = 76.49 kJ /mol

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How many grams of hydrogen is produced from 12.5 G of MG reacting with hydrochloric acid in this balanced equation?
k0ka [10]

Answer:

1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.

Explanation:

The balanced reaction is:

Mg+ 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

  • Mg: 1 mole
  • HCl: 2 moles
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  • H₂: 1 mole

Being the molar mass of each compound:

  • Mg: 24.31 g/mole
  • HCl: 36.45 g/mole
  • MgCl₂: 95.21 g/mole
  • H₂: 2 g/mole

By reaction stoichiometry, the following mass amounts of each compound participate in the reaction:

  • Mg: 1 mole* 24.31 g/mole= 24.31 g
  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
  • H₂: 1 mole* 2 g/mole= 2 g

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg produces 2 grams of H₂, 12.5 grams of Mg produces how much mass of H₂?

mass of H_{2} =\frac{12.5 grams of Mg* 2 grams of H_{2}}{24.31 grams of Mg}

mass of H₂= 1.03 grams

<u><em>1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.</em></u>

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