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How the hydrosphere and biosphere interact in this swamp?

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1 answer:

bonufazy [111]3 years ago

3 0

Answer:

heat from the sun and heat flowing out of earth as it cools.

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Answer: 0.209 M

Explanation:

Moles of $CO_2$ = 2.00 mole

Moles of $H_2$ = 1.50 mole

Volume of container = 5.00 L

Initial concentration of $CO_2$ = $\frac{moles}{Volume}=\frac{2.00mol}{5.00L}=0.400M$

Initial concentration of $H_2$ = $\frac{moles}{Volume}=\frac{1.50mol}{5.00L}=0.300M$

The given balanced equilibrium reaction is,

$CO_2(g)+H_2(g)\rightleftharpoons CO(g)+H_2O(g))$

Initial conc. 0.400 M 0.300M 0 M 0 M

At eqm. conc. (0.400-x) M (0.300-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [H_2O]}{[H_2]\times [CO_2]}$

Now put all the given values in this expression, we get :

$2.50=\frac{[x]\times [x]}{[0.300-x]\times [0.400-x]}$

By solving the term 'x', we get :

x = 0.209 M

Concentration of $CO$ at equilibrium = x M = 0.209 M

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