Question

You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.80 mA when a sinusoidal voltage with amplitude 12.0 V is applied across the inductor. What frequency is required?

Answer 1

Answer:

2.36 x 10^6 Hz

Explanation:

We know ;,

Iamp = 1.8mA

L = 0.45mH

VL = 12V

VL = IwL

VL = I x 2π x f x L

f = VL / (I x 2π x L)

f = 12 V/ (1.8mA x 2π x 0.45mH)

f = 12/(1.8x10^-3 x 2π x 0.45 x 10^-3)

f = 2.36 x 10^6 Hz