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Paha777 [63]
4 years ago
7

You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.80 mA when a sin

usoidal voltage with amplitude 12.0 V is applied across the inductor. What frequency is required?
Physics
1 answer:
Anika [276]4 years ago
5 0

Answer:

2.36 x 10^6 Hz

Explanation:

We know ;,

Iamp = 1.8mA

L = 0.45mH

VL = 12V

VL = IwL

VL = I x 2π x f x L

f = VL / (I x 2π x L)

f = 12 V/ (1.8mA x 2π x 0.45mH)

f = 12/(1.8x10^-3 x 2π x 0.45 x 10^-3)

f = 2.36 x 10^6 Hz

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Leokris [45]

Answer:

a

Explanation:

6 0
3 years ago
I WILL GIVE BRAIN LIST PLS HELP
Dominik [7]

Answer:

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4 0
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How does wavelength change depending on whether the pipe is open or closed?
il63 [147K]

Answer:

* in a tube with both ends open

        λ = 2L / n                    n = 1, 2, 3,…

* tube with one end open and the other closed.  

         λ = 4L / n                     n = (2n ’+ 1 )

Explanation:

When a sound wave enters a pipe, a resonance process occurs, whereby only some wavelengths can occur.

 

* in a tube with both ends open

in this case there are maximums at each end, so if the length of the had is L

              λ = 2L 1st harmonic

              λ = 2 L / 2 2nd harmonic

              λ = 2L / 3

              λ = 2L / n                    n = 1, 2, 3,…

* In the case of a tube with one end open and the other closed.

At the open end there is a belly and at the closed end a node

              λ = 4L 1st harmonic

              λ = 4L / 3 3rd harmonic

              λ = 4L / 5

              λ = 4L / n                  n = 1, 3, 5,… odd

                                       n = (2n ’+ 1 )      where n’ are all integers

4 0
3 years ago
Hello, I need help answering and explaining the question in the attached image. It includes the figures plus the question and th
Flauer [41]

Answer:

d.

Explanation:

Since the dart's initial speed v at angle has both vertical and horizontal components v₀sinθ and v₀cosθ respectively, the vertical component of the speed continues to decrease until it hits the target. It's displacement ,s is gotten from

s = y - y₀ = (v₀sinθ)t - 1/2gt² where y₀ = 0 m

y - 0 = (v₀sinθ)t - 1/2gt²

y = (v₀sinθ)t - 1/2gt²

which is the parabolic equation for the displacement of the dart.

Note that the horizontal component of the dart's velocity does not change during its motion.

Since the target falls vertically, with initial velocity u = 0 (since it was stationary before the string cut), it's displacement ,s' is gotten from

s' = y - y₀' = ut - 1/2gt² where y₀' = initial height of target above the ground

= (0 m/s)t - 1/2gt²

= 0 - 1/2gt²

y - y₀' = - 1/2gt²

y = y₀' - 1/2gt²

which is the parabolic equation for the displacement of the target.

The equation for both the displacement of the dart and the target can only be gotten if we considered vertical motion. So, the displacement component of both the dart and target are both vertical.

So, the answer is d.

8 0
3 years ago
Please help me I will give you 20 points !!
nadezda [96]

Answer:

D. The primary source, because it was written by the researcher

Explanation:

One should learn to trust the primary source more because it is the real work of the researcher.

A primary work defines the work of research from his or her experimental findings.

  • The primary source presents experimental data and other subordinates ones to reach a conclusion as seen from the view of the researcher.
  • A secondary source implies someone else documenting their own opinion about the primary experimental set up.
  • This can get dicey in the sense that results can be twisted to serve other ulterior motives.

8 0
3 years ago
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