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bogdanovich [222]
3 years ago
9

What is the specific heat of silicon if the temperature of a 4.11 g sample of silicon

Chemistry
1 answer:
monitta3 years ago
4 0

Answer:

The right solution is "0.7107 J/g°C".

Explanation:

The given values are:

Mass,

m = 4.11 g

Temperature,

ΔT = 3.8°C

Heat,

Q = 11.1 J

The specific heat of silicon will be:

⇒  C=\frac{Q}{m \Delta T}

On substituting the values, we get

⇒      =\frac{11.1}{4.11\times 3.8}

⇒      =\frac{11.1}{15.618}

⇒      =0.7107 \ J/g^{\circ}C

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The figure below shows the products of the cycle after 3 turns (Source: https://ka-perseus-images.s3.amazonaws.com/2f4bdc8f8275834d3f5ef434d93bf16b991b2357.png). 

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