Question

What is the specific heat of silicon if the temperature of a 4.11 g sample of silicon

Answer 1

Answer:

The right solution is "0.7107 J/g°C".

Explanation:

The given values are:

Mass,

m = 4.11 g

Temperature,

ΔT = 3.8°C

Heat,

Q = 11.1 J

The specific heat of silicon will be:

⇒  $C=\frac{Q}{m \Delta T}$

On substituting the values, we get

⇒      $=\frac{11.1}{4.11\times 3.8}$

⇒      $=\frac{11.1}{15.618}$

⇒      $=0.7107 \ J/g^{\circ}C$