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3 years ago

A car travels 60 miles due West first then turns back and travels 120 miles due East in 3 hours. What is...

Physics

1 answer:

ella [17]3 years ago

7 0

Answer:

<h2>A. 180 miles</h2><h2>B. 60 miles</h2><h2 />

Explanation:

In this problem, we are required to solve for the total distance that the car travelled. and the displacement

A) the distance travelled by car

this can be gotten by summing all the distances the car has travelled.

i,e total distance= 60 miles+120 miles

total distance= 180 miles

B) the displacement of the car

the displacement can be gotten by subtracting the final distance from the initial distance

final distance = 120 miles

initial distance= 60 miles

displacement= 120-60= 60 miles

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- farmer has recently bought a 40 acre land and wishes to fence the perimeter. given that the Land is square, what lenght of fen

goldfiish [28.3K]

Answer:

Explanation:

4√((40(4046)) = 1,609.17370... = 1609 m

3 0

2 years ago

Two identical cars, one on the moon and one on the earth, have the same speed and are rounding banked turns that have the same r

Naily [24]

Answer:

The value of the centripetal forces are same.

Explanation:

Given:

The masses of the cars are same. The radii of the banked paths are same. The weight of an object on the moon is about one sixth of its weight on earth.

The expression for centripetal force is given by,

$F_{c} = \dfrac{mv^{2}}{r}$

where, $m$ is the mass of the object, $v$ is the velocity of the object and $r$ is the radius of the path.

The value of the centripetal force depends on the mass of the object, not on its weight.

As both on moon and earth the velocity of the cars and the radii of the paths are same, so the centripetal forces are the same.

3 0

2 years ago

A nature photographer is using a camera that has a lens with a focal length of 3.06 cm. The photographer is taking pictures of a

sleet_krkn [62]

Answer:

film is at distance of 3.07 cm from lens

Explanation:

Given data

focal length = 3.06 cm

distance = 10.4 m = 1040 cm

to find out

How far must the lens

solution

we apply here lens formula that is

1/f = 1/p + 1/q

here f = 3.06 and p = 1040 so we find q

1/f = 1/p + 1/q

1/3.06 = 1/1040 + 1/q

1/ q = 0.3258

q = 3.0690 cm

so film is at distance of 3.07 cm from lens

6 0

3 years ago

A 420N force act on a 400N object, and the force is from the north.

belka [17]

Answer:

I believe its forward or south :D

Explanation:

7 0

2 years ago

Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te

alexgriva [62]

Answer:

4.9 minutes

Explanation:

Given; T(t) = Ce^-kt + Ts

Now;

T(t) = 190 degrees Fahrenheit

Ts = 60 degrees

To obtain C;

190 = Ce^0 + 60

190 - 60 = C

C = 130

Hence, to find k when t=11

172 = 130 e^-11k + 60

172 -60/130 = e^-k

e^-k = 0.86

ln(e^-k) = ln( 0.86)

-k = -0.15

k = 0.15

Hence at 122 degrees, t is;

T(t) = Ce^-kt + Ts

122 = 130e^-0.15t + 60

122 - 60/130 = e^-0.15t

0.477 = e^-0.15t

ln (e^-0.15t) = ln (0.477)

-0.15t = -0.74

t = 0.74/0.15

t = 4.9 minutes

5 0

3 years ago