Impulse = Ft=mΔv => Δv = Ft/m = 4.28/0.18 = 23.78 m/s
But,
Δv = v1-v2, where v1 = initial velocity = 16 m/s, v2 = final velocity
Therefore,
v1 - v2 = 23.78 => v2 = v1 - 23.78 => v2 = 16 - 23.78 = -7.78 m/s
The velocity of ball after the force is 7.78 m/s in the direction of the force.
from one energy form to one
Answer:
When a negative charge is brought near one end of a conductor electrons are repelled. ... When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.
<h2>
Velocity of 0.2 kg ball is 0.17 m/s</h2>
Explanation:
Let the mass of balls be m and M.
Initial velocity ball 1 be u₁, ball 2 be u₂
Final velocity ball 1 be v₁, ball 2 be v₂
Initial momentum = m x u₁ + M x u₂ = 0.2 x 0.3 + 0.1 x 0.1 = 0.07 kgm/s
Final momentum = m x v₁ + M x v₂ = 0.2 x v₁ + 0.1 x 0.36 = 0.2v₁ + 0.036
We have momentum conservation
Initial momentum = Final momentum
0.07 = 0.2v₁ + 0.036
v₁ = 0.17 m/s
Velocity of 0.2 kg ball is 0.17 m/s
