Question

Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act. One acrobat has a mass of 60 kg and has a horizontal velocity of 5 m/s just before the grab. Another acrobat has a mass of 50 kg and has a horizontal velocity of -3 m/s just before the grab. Their horizontal velocity immediately after they grab onto each other is:
A. 1.4 m/s
B. 3.0 m/s
C. 0.6 m/s
D. 2.0 m/s
E. 4.1 m/s

Answer 1

Answer:

Final velocity will be 1.4 m/sec

So option (a) is correct option

Explanation:

We have given there are two acrobats

Mass of first acrobats $m_1=60kg$ and its velocity $v_1=5m/sec$

Mass of second acrobats $m_2=50kg$ and its velocity $v_2=-3m/sec$

Now from conservation of momentum we know that

$m_1v_1+m_2v_2=(m_1+m_2)v$

$60\times 5+50\times (-3)=(50+60)v$

$v=1.36=1.4m/sec$

So option (a) is correct option

Answer 2

Answer:1.4 m/s

Explanation:

Given

mass of first acrobat $m_1=60 kg$

velocity $v_1=5 m/s$

mass of second acrobat $m_2=50 kg$

velocity $v_2=-3 m/s$

let us take v be the final velocity of two acrobats

$m_1\cdot v_1+m_2\cdot v_2=(m_1+m_2)v$

$60\times 5-50\times 3=(60+50)v$

$v=\frac{300-150}{110}$

$v=\frac{15}{11}=1.36 a\pprox 1.4 m/s$