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3 years ago

Can someone please check my answer??!!

Chemistry

1 answer:

alex41 [277]3 years ago

5 0

G cancels out leaving only J.

Since there is a g in the numerator and a g in the denominator, both gs can be cancelled. This leaves the J in the numerator as the final units.

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the ph of a solution of HCl in water is found to be 2.50. what volume of water would you add to 1.00L of this solution to raise

morpeh [17]

Answer:

To raise the pH of the solution to 3.10 we have to add 2.34 L of water.

Explanation:

Given that the pH of the solution of HCl in water is 2.5. Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution. $[H^+]$ ions contribute to a solution’s acidic nature and $[OH^-]$ contribute to a solution’s basic nature.

The equation connecting the concentration of $[H^+]$ and pH of a solution is pH= $-log[H^+]$

 $[H^+]= 10^(^-^p^H^)$ $[H^+]= 10^(^-^2^.^5^)=0.00316$ 

When the pH is $3.1 [H^+ ]= 10^(^-^3^.^1^)=0.000794$ 

On dilution the concentration of a solution decreases and volume increases.

 $M_1 V_1 = M_2 V_2$ 

 $0.00316 \times 1 = 0.000794 \times V_2$ 

 $V_2 = \frac{(0.00316 \times 1)}{0.000794} =3.24$ 

Volume of water to be added $=3.24-1$ 

 $=2.24L$ 

6 0

3 years ago

A chemist must dilute of aqueous potassium dichromate solution until the concentration falls to . He'll do this by adding distil

Phantasy [73]

The question is incomplete; the complete question is;

A chemist must dilute 99.4 mL of 152 mM aqueous potassium dichromate (K_2Cr_2O_7) solution until the concentration falls to 55.0 mM He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

0.275 L

Explanation:

From C1V1 = C2V2

Where;

C1= initial concentration of the solution 152 × 10^-3 M

V1= initial volume of the solution = 99.4 × 10^-3 L

C2 = concentration after dilution = 55 × 10^-3 M

V2 = volume after dilution = the unknown

V2 = C1 V1/C2

V2 = 152 × 10^-3 × 99.4 × 10^-3 / 55 × 10^-3

V2 = 0.275 L

5 0

3 years ago

Homogenous mixture are?

siniylev [52]

Well in the technical sense, we normally establish these as solutions, but in a practical world it is common to call them solutions. Although this is all true, I refer to this beautiful item of chemistry as the sir mix a lot of chemicals

8 0

4 years ago

URGENT HELP NEEDED

balu736 [363]

the balanced equation for the reaction is as follows
2C₄H₁₀ + 13O₂ ---> 8 CO₂ + 10H₂O
stoichiometry of C₄H₁₀ to O₂ is 2:13
stoichiometry applies to the molar ratio of reactants and products. Avagadros law states that volume of gas is directly proportional to number of moles of gas when pressure and temperature are constant.
Therefore volume ratio of reactants is equal to molar ratio, volume ratio of C₄H₁₀ to O₂ is 2:13
2 L of C₄H₁₀ reacts with 13 L of O₂
then 100 L of C₄H₁₀ reacts with 13/2 x 100 = 650 L
therefore 650 L of O₂ are required

7 0

3 years ago

Read 2 more answers

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Assoli18 [71]

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8 0

3 years ago