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solong [7]
3 years ago
9

Which of the following elements is an example of a metalloid?

Chemistry
2 answers:
8_murik_8 [283]3 years ago
8 0
Sodium is an earth-metal (group one), sliver and platinum are d-block metals.... Thus silicon is the metalloid and that is true because it looks like a metal being shiny blue-gray but it exhibit non-metal characteristics, except the fact that it can conduct electricity in a heated state.
lesya692 [45]3 years ago
6 0
The group of metalliods in the periodic table include: antimony, arsenic, boron, silicon, germanium, polonium all display semi-metal properties. So the answer would be Silicon.
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How many moles of HNO3 will be produced 3 NO2+H2O=2HNO3+ NO
valkas [14]

Answer:

2 moles of HNO3

Explanation:

The equation seems to be balanced correctly. The problem is we done know what you started with. We will assume it is 3 moles of NO2.

If that is the case then 2 moles of HNO3 will be produced.

8 0
3 years ago
Ions Types of Ions Cation Anion 1. H+ 2.O-2 3.Ba2+ 4.Br- 5.Hg2+ 6.Li+ 7.Ca2+ 8.F- 9.S-2 10.Fe3+
fiasKO [112]

Explanation:

The species with a positive charge over it, which means lack of electrons are called cations. Whereas the species with negative over it, meaning it has an excess of electrons with it are called anions.

From the list given the cations are

H+, Ba2+, Hg2+, Li+, Ca2+ and Fe2+

Whereas anions from the list are

O-2, Br-5, F-, S-2.

A Combination of cation and anions make an ionic compound in which cation is written first and then anion.

6 0
3 years ago
There are four hundred participants in the local Thanksgiving 5K race. If 51% of the participants are female, what is the ratio
Paha777 [63]

Answer:

51:49 is the ratio of female participants to male participants.

Explanation:

Percentage of females in the race = 51 %

Percentage of males in the race = 100% - 51 % = 49%

Total participants in race = 400

Number of women participants = 51% of 400=\frac{51}{100}\times 400=204

Number of men participants  = 49% of 400=\frac{49}{100}\times 400=196

Ratio of female participants to male participants :

\frac{204}{196}=\frac{51}{49}=51:49

5 0
3 years ago
Do all colors of light travel at the same speed
bogdanovich [222]

Answer:

No because some lights we cannot see because they move to slow or they move to fast for our eye to see. There is just a small little gap compared to what light rays we can actually see. In this picture you can see what I mean.

Explanation:

5 0
3 years ago
Read 2 more answers
In Experiment 9, a 1.05 g sample of a mixture of NaCl (MW 58.45) and NaNO2 (MW 69.01) is reacted with excess sulfamic acid. The
Kaylis [27]

Answer:

There is 76.6 mL of nitrogen collected

Explanation:

<u>Step 1: </u>Data given

Mass of the sample = 1. 05 grams

The sample is 40.00% by mass NaNO2

MW of NaCl = 58.45 g/mol

MW of NaNO2 = 69.01 g/mol

Temperature = 22.0 °C

Pressure = 750.0 mmHg = (750/760) atm

The vapor pressure of water at 22.0°C is 19.8 mm Hg = 0.02605 atm

<u>Step 2:</u> Calculate mass of NaNO2

(40/100)*1.05  = 0.42 grams

<u>Step 3:</u> Calculate moles of NaNO2

Moles NaNO2 = 0.42 grams / 69.01 g/mol

Moles NaNO2 = 0.00608 moles

<u>Step 4:</u> Calculate moles of N2

For 2 moles of NaNO2 we'll get 1 mol of N2

For 0.00608 moles of NaNO2 we'll get 0.00608/2 = 0.00304 moles

<u>Step 5:</u> Calculate pressure of N2

P = 750.0 - 19.8 = 730.2 mmHg = (730.2/760)atm = 0.96079 atm = 97352 Pa

<u>Step 6:</u> Calculate volume of N2

PV = nRT

⇒ P = the pressure of N2 =  0.96079

⇒ V = the volume of N2 = TO BE DETERMINED

⇒ n = moles of N2 = 0.00304 moles

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 22°C = 295 Kelvin

V = (0.00304*0.08206*295)/0.96079

V = 0.0766 L = 76.6 mL

There is 76.6 mL of nitrogen collected

4 0
4 years ago
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