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3 years ago

0.47 moles MgCO3 to g. 450.2 g LiNO3 to moles 36.8g Br2 to molecules

Chemistry

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

Answer:

- 39.6 g of MgCO₃

- 6.53 moles of LiNO₃

- 1.38×10²³ molecules of Br₂

Explanation:

Let's make some conversions here:

- 0.47 moles of MgCO₃ to g.

We should know, the molar mass of carbonate: 84.3 g /mol

0.47 mol . 84.3 g / 1mol = 39.6 g

- 450.2 g of LiNO₃

Molar mass of nitrate: 68.94 g/mol

450.2 g . 1 mol /68.94g = 6.53 moles of LiNO₃

- Molar mass for dyatomic bromine: 159.80 g/mol

36.8 g . 1 mol/159.80 g = 0.230 moles

1 mol has 6.02×10²³ molecules

0.230 mol . 6.02×10²³ molecules / 1 mol = 1.38×10²³ molecules of Br₂

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A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o

statuscvo [17]

Answer: The value of $K_{eq}$ is 0.044

Explanation:

We are given:

Initial moles of methane = $4.10\times 10^{-2}mol=0.0410moles$

Initial moles of carbon tetrachloride = $6.51\times 10^{-2}mol=0.0651moles$

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of methane = $\frac{0.0410}{1.00}=0.0410M$

Concentration of carbon tetrachloride = $\frac{0.0651}{1.00}=0.0651M$

The given chemical equation follows:

$CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)$

Initial: 0.0410 0.0651

At eqllm: 0.0410-x 0.0651-x 2x

We are given:

Equilibrium concentration of carbon tetrachloride = $6.02\times 10^{-2}M=0.0602M$

Evaluating the value of 'x', we get:

$\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M$

Now, equilibrium concentration of methane = $0.0410-x=[0.0410-0.0049]=0.0361M$

Equilibrium concentration of $CH_2Cl_2=2x=[2\times 0.0049]=0.0098M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044$

Hence, the value of $K_{eq}$ is 0.044

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sdas [7]

Answer:

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3 years ago

Which of these substances acts as a buffer? a. blood b. lemon juice c. curd

il63 [147K]

The correct answer is( A) blood.

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3 years ago

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Answer:

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Answer:

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Explanation:

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