Given a right triangle with base, b and height, h with the angle opposide side h as θ.
The area of a triangle is given by

But,

Therefore, the area of the triangle in terms of <span>b and θ only is given by
</span>
Rational numbers.
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Answer:
(a)then the product of these two numbers is divisible by 6.
Step-by-step explanation:
If a and b are two integers where at least one of a or b is divisible by 6, the product ab will also be divisible by 6.
If, a is divisible by 6, a/6 = c (an integer).
Product of a and b, (ab)/6 = (a/6) X b =cb.
Likewise if b is divisible by 6, same rule applies.
We only need a term in the product to be divisible by an integer for the product to be divisible by the integer.
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Answer:
The correct option is B:
Subtract 2 from both sides
Step-by-step explanation:
We have the equation x²-4x+16=2
The first step to solve this equation is:
Subtract 2 from both sides
We get;
x²-4x+16=2
x²-4x+16-2=2-2
x²-4x+14=0
Now this is the quadratic equation. You can use quadratic formula to solve this equation....