Just divide the both, you will get the answer!
does it sound rude?
im sorry for that!
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
<h3>
Work done by the applied force</h3>
The work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
<h3>Work done by frictional force</h3>
W = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
<h3>Net work done by all the forces on the tractor</h3>
W(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
Learn more about work done here: brainly.com/question/25573309
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Energy consumed in doing the work = 300 Joules
Force applied on the object = 75 N
Let the distance moved by the object be d.
Work done by the force is determined by the force applied and the displacement happened in the direction of the force applied.
Work done = Force x displacement
300 = 75 x d

d = 4 m
Hence, the maximum distance moved by the object = 4 meters
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