Answer:
The minimum possible coefficient of static friction between the tires and the ground is 0.64.
Explanation:
if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :
Fc = f
m×(v^2)/(R) = μ×m×g
(v^2)/(R) = g×μ
μ = (v^2)/(R×g)
= ((25)^2)/((100)×(9.8))
= 0.64
Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.
Answer:
i don't know if this is right but here,9900 kgm/s
Explanation:
calculator UwU
<span>Density can be determined by the
mass of an object and how much it takes up space (volume). It is represented by
the formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the mass
in kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of an
object of 40.5kg and a volume of 15m^3. Find its density.</span>
D = M/V
D = (40.5 kg)
/ (15 m^3)
<span>D = 27/10 or
2.7 kg/m^3 </span>
4 blue = 3 white
x blue = 12 white?
Cross multiply
48 = 3x
x = 16 blue
Another way to do this is figure how many times 3 whites go into 12 whites.
That's 4 times.
So 4 blue x 4 = 16 blue
This is happened because "the air" above "moves faster" and "the pressure" is "lower"
.
Option: 1
<u>Explanation</u>:
Air movement take place from the region where air pressure is more than the region where the pressure is low. When we "blow" air above the "paper strip" paper rises because "low pressure" is created above the strip as high speed winds always travel with reduced air pressure. Hence due to higher air pressure below the strip, it is pushed upwards. This difference in pressure results into fast air moves. This happen because "speed" of the wind depends on "the difference between the pressures" of the air in the two regions.
