Answer:
2.9 is the initial pH of the analyte solution.
Explanation:
The dissociation constant of acetic acid as per theoretical value = 

The initial concentration of acetic acid = c = 0.0900 M

initially
c 0 0
At equilibrium
(c-x) x x
The expression of dissociation constant :
![K_a=\frac{[Ac^-][H^+]}{[HAc]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BAc%5E-%5D%5BH%5E%2B%5D%7D%7B%5BHAc%5D%7D)


Solving for x:
x = 0.001264 M
![[H^+]=0.001264 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.001264%20M)
The pH of the solution :
![pH=-\log[0.001264]=2.898\approx 2.9](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B0.001264%5D%3D2.898%5Capprox%202.9)
2.9 is the initial pH of the analyte solution.
Electrons are orbiting the nucleus in the fxed way paths located in solid sphere
Answer:
Syrup is a mixture of thick sticky liquid consisting of a concentrated solution of sugar and water with or without the addition of a flavoring agent or medicinal substance.
Explanation:
so compound
Answer:
3.955*10^48
Explanation:
1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48
<h3>Answer:</h3>
Molecular Formula = S₂O₂ (Disulfur Dioxide)
<h3>Solution:</h3>
Molecular formula is calculated by using following formula,
Molecular Formula = n × Empirical Formula ---- (1)
Also, n is given as,
n = Molecular Weight / Empirical Formula Weight
Molecular Weight = 96.13 g.mol⁻¹
Empirical Formula Weight = 32.06 (S) + 16.0 (O) = 48.06 g.mol⁻¹
So,
n = 96.13 g.mol⁻¹ ÷ 48.06 g.mol⁻¹
n = 2.0002 ≈ 2
Putting Empirical Formula and value of "n" in equation 1,
Molecular Formula = 2 × SO
Molecular Formula = S₂O₂ (Disulfur Dioxide)