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garri49 [273]
3 years ago
8

A local am radio station broadcasts at a wavelength of 349m, calculate the energy of the wavelength at which it is broadcasting?

a. 5.69 x 10^-19 J b. 6.93 x 10^-39 J c. 8.59 x 10^5 J d. 6.33 x10^-45 J e. 7.71 x 10^-40 J
Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

E = 5.69x10⁻²⁸m

Explanation:

To solve this question we neeed to convert the wavelength in meters to energy in joules using the equation:

E = hc / λ

<em>Where E is energy in joules, h is Planck's constant = 6.626x10⁻³⁴Js</em>

<em>c is light constant = 3.0x10⁸m/s</em>

<em>And λ is wavelength in meters = 349m</em>

Replacing:

E = 6.626x10⁻³⁴Js*3.0x10⁸m/s / 349m

E = 5.69x10⁻²⁸m

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Answer:

2.9 is the initial pH of the analyte solution.

Explanation:

The dissociation constant of acetic acid as per theoretical value =  K_a

K_a=10^{-4.756}=1.8\times 10^{-5}

The initial concentration of acetic acid = c = 0.0900 M

HAc\rightleftharpoons Ac^-+H^+

initially

c       0    0

At equilibrium

(c-x)      x  x

The expression of dissociation constant :

K_a=\frac{[Ac^-][H^+]}{[HAc]}

1.8\times 10^{-5}=\frac{x\times x}{(c-x)}

1.8\times 10^{-5}=\frac{x\times x}{(0.0900-x)}

Solving for x:

x = 0.001264 M

[H^+]=0.001264 M

The pH of the solution :

pH=-\log[0.001264]=2.898\approx 2.9

2.9 is the initial pH of the analyte solution.

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What is the molecular formula of a compound with the empirical formula so and molecular weight 96.13?
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<h3>Answer:</h3>

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<h3>Solution:</h3>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

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