Answer:
solids
Explanation:
through solids because the molecules are closer together
Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.
Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
0.300 M IKI represents the
concentration which is in molarity of a potassium iodide solution. This means
that for every liter of solution there are 0.300 moles of potassium iodide. Knowing
that molarity is a ratio of solute to solution.
By using a conversion factor:
100 ml x (1L / 1000 mL) x (0.300
mol Kl / 1 L) x (166.0g / 1 mol Kl) = 4.98 g
Therefore, in the first
conversion by simply converting the unit of volume to liter, Molarity is in L
where the volume is in liters. The next step is converted in moles from volume
by using molarity as a conversion factor which is similar to how density can be
used to convert between volume and mass. After converting to moles it is simply
used as molar mass of Kl which is obtained from periodic table to convert from
mole to grams.
In order to get the grams of IKI
to create a 100 mL solution of 0.600 M IKI, use the same formula as above:
100 ml x (1L / 1000 mL) x (0.600
mol Kl / 1 L) x (166.0g / 1 mol Kl) = 9.96 g
Energy can be renewable or nonrenewable.
The complete chemical formula for the unknown compound is N2O3 where X = 2 which is the oxidation state of oxygen.
<h3>What is oxidation state?</h3>
Oxidation state is the number of electron which the compound is giving or taking from each other to form the bonds as the oxidation is hight oxidation is happening asn if the low then reduction is happening.
In the compound N2O3 the oxidation state of O is 2 and the oxidation stte of N is 3 written in the cross-cross manner in compound.
Therefore, N2O3 where X = 2 which is the oxidation state of oxygen is complete chemical formula for the unknown compound.
Learn more about oxidation state, here:
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