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Paladinen [302]
3 years ago
13

What is the molarity of a 3.0-liter solution that contains 0.45 moles of solute

Chemistry
2 answers:
sergeinik [125]3 years ago
6 0
Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.

Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
 I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
Ksivusya [100]3 years ago
5 0

Answer : The molarity of the solution is, 0.15 mole/L

Solution :

Molarity : It is defined as the number of moles of solute present in one liter of the solution.

Formula used :

Molarity=\frac{\text{moles of solute}}{\text{Volume of solution in liters}}

Now put all the given values in this formula, we get the molarity of the solution.

Molarity=\frac{0.45mole}{3L}=0.15mole/L

Therefore, the molarity of the solution is, 0.15 mole/L

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Which of the following samples will have the lowest pressure if they are all at the same temperature and in identical containers
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Answer:

c. 15 g Kr

Explanation:

The amount of a gas (Moles) is directely proportional to its pressure. That means the higher amount of moles, the highest pressure and vice versa.

Using molar mass of the compounds (Ne=20.2g/mol, Ar = 39.9g/mol, Kr = 83.8g/mol, CO₂ = 44 g/mol and F₂ = 38.0g/mol), moles of 15.0g of each gas are:

Ne = 15g ₓ (1mol / 20.2g) = <em>0.74 moles of Ne</em>

Ar = 15g ₓ (1mol / 39.9g) = <em>0.38 moles of Ar</em>

Kr = 15g ₓ (1mol / 83.8g) = <em>0.18 moles of Kr</em>

CO₂ = 15g ₓ (1mol / 44g) = <em>0.34 moles of CO₂</em>

F₂ = 15g ₓ (1mol / 38g) = <em>0.39 moles of F₂</em>

<h3>As 15g of Kr contains the less quantity of moles, this sample will con have the lowest pressure</h3>
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List three ways the rate of solvation of sodium chloride in water may be<br> increased
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Coal can be used to generate hydrogen gas (a potential fuel) by thefollowing endothermic reaction.C(s) + H2O (g) &lt;==&gt; CO(g
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Explanation:

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This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

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For the given options:

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If the concentration of C that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of C takes place. Therefore, the equilibrium will shift in the right direction to wards the formation of hydrogen gas.

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If the concentration of water that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of water  takes place. Therefore, the equilibrium will shift in the right direction towards the formation of hydrogen gas.

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If the temperature is increased,heat of the equilibrium mixture will also increase so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in heat that is decrease in temperature occurs.

As, this is an endothermic reaction, forward reaction will decrease the temperature. Hence, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.  

d) Increasing the volume  of reaction mixture

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e) Adding a catalyst  to reaction mixture

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f) Adding an inert gas to reaction mixture

Adding inert gas to the mixture at constant volume will not effect the equilibrium. Hence, addition of an inert gas will not change the equilibrium of the reaction.  

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