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Paladinen [302]
2 years ago
13

What is the molarity of a 3.0-liter solution that contains 0.45 moles of solute

Chemistry
2 answers:
sergeinik [125]2 years ago
6 0
Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.

Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
 I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
Ksivusya [100]2 years ago
5 0

Answer : The molarity of the solution is, 0.15 mole/L

Solution :

Molarity : It is defined as the number of moles of solute present in one liter of the solution.

Formula used :

Molarity=\frac{\text{moles of solute}}{\text{Volume of solution in liters}}

Now put all the given values in this formula, we get the molarity of the solution.

Molarity=\frac{0.45mole}{3L}=0.15mole/L

Therefore, the molarity of the solution is, 0.15 mole/L

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Assume density of H2O = 1 g/ml

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m = 0.6g NH4Cl/ml

See the table of saturated solutions and identify the temperature at which the concentration of NH4Cl is 60g/100g H2O.

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2 years ago
There are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. If the solubility of zinc
zhuklara [117]

Answer:

K_{sp} of Zn(CH_{3}COO)_{2} is 0.0513

Explanation:

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Solubility product of Zn(CH_{3}COO)_{2} (K_{sp}) is written as-            K_{sp}=[Zn^{2+}][CH_{3}COO^{-}]^{2}

Where [Zn^{2+}] and [CH_{3}COO^{-}] represents equilibrium concentration (in molarity) of Zn^{2+} and CH_{3}COO^{-} respectively.

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1 mol of Zn(CH_{3}COO)_{2} gives 1 mol of Zn^{2+} and 2 moles of CH_{3}COO^{-} upon dissociation.

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so, K_{sp}=(0.234)\times (0.468)^{2}=0.0513          

8 0
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Answer:

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