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diamong [38]
3 years ago
5

It is important to use ______ sources of information to evaluate strengths and weaknesses of claims, arguments, or data.

Physics
2 answers:
Lemur [1.5K]3 years ago
6 0
D.multiple. because you always have to double check to see if its true or not. Majority rule.
quester [9]3 years ago
6 0
It would be D. The reason is because you always want to cross-reference your information of multiple, reliable sites to confirm (Or deny) you information. For example, if I googled "Do cats really have nine lives?" The results appear as a study from a college in New York and an article about cats. You can't really trust a random website, as anyone can edit it and make it inaccurate. That means you should just read the study, right? Wrong. You should read both of the pages, and find which parts seem to be in both of them. These parts are likely accurate, because they were on two different sources.
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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
inysia [295]
Newton' 1st Law of Motion

A soccer ball will not move until a player kicks it

A bowling ball hits the pins sending the pins flying for a STRIKE!


Newton's 2nd Law of Motion

it takes less force to move a ping pong ball then a bowling ball.

f - ma


Newton's 3rd Law of Motion

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5 0
3 years ago
What are earths two main motions called
andre [41]
Rotation and revolution
3 0
3 years ago
In a given system of units the ratio of the unit of volume to that of area gives the unit of​
ch4aika [34]

Answer:

length

Explanation:

SI unit of volume = m^3

SI unit of area = m^2

volume unit / Area unit = m^3 / m^2

i.e, unit of length

8 0
3 years ago
Combustion reactions are also ________ reactions. A. nuclear B. exothermic C. endothermic D. spontaneous
sveta [45]
I think is a) i hope this hlp
5 0
3 years ago
Read 2 more answers
A hypothetical planet has a mass of one-half that of the earth and a radius of twice that of the earth.
Fed [463]
<h2>Option A is the correct answer.</h2>

Explanation:

Acceleration due to gravity

                  g=\frac{GM}{r^2}

         G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

  Let mass of earth be M and radius of earth be r.

  We have

               g=\frac{GM}{r^2}

Now

         A hypothetical planet has a mass of one-half that of the earth and a radius of twice that of the earth.

       Mass of hypothetical planet, M' = M/2

       Radius of hypothetical planet, r' = 2r

  Substituting

              g'=\frac{GM'}{r'^2}\\\\g'=\frac{G\times \frac{M}{2}}{(2r)^2}\\\\g'=\frac{\frac{GM}{r^2}}{8}\\\\g'=\frac{g}{8}

Option A is the correct answer.

6 0
3 years ago
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