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Gennadij [26K]
3 years ago
13

As the voltage across a resistor is increased, what happens to the resistance of the resistor?

Chemistry
2 answers:
vampirchik [111]3 years ago
7 0
<h3>HELLO THERE, I HOPE MY ANSWER WILL HELP YOU :)</h3>

<h2>ANSWER-</h2>

-We will be paying close attention to the Ohm’s Law here:-

>Ohm's law states that the electrical current (I) flowing in an circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). >Therefore, if the voltage is increased, the current will increase provided the resistance of the circuit does not change.

iVinArrow [24]3 years ago
6 0

Answer:

your answer is wrong dear\huge\boxed{\fcolorbox{cyan}{pink}{ello}}

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At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
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Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

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P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

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x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

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A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
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Answer:

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In the reaction:

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As ΔH >0,

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<em />

As the reaction is endothermic, when the reaction occurs,

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