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3 years ago

If 298 mL of 0.575 M CuCl2 is diluted into 750 mL, what is the concentration of new solution?

Chemistry

1 answer:

Sonja [21]3 years ago

4 0

Answer:

<h3>The answer is 0.228 M</h3>

Explanation:

To find the concentration of new solution we use the formula

$C_1V_1 = C_2V_2$

where

C1 is the concentration of the stock solution

V1 is the volume is the volume of the stock solution

C_2 is the concentration of the diluted solution

V2 is the volume of the diluted solution

Since we are finding the the concentration of new solution

$C_2 = \frac{C_1V_1}{V_2} \\$

From the question

C1 = 0.575 M

V1 = 298 mL

V2 = 750 mL

We have

$C_2 = \frac{0.575 \times 298}{750} \\ = 0.228466666...$

We have the final answer as

Hope this helps you

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