Question

If 298 mL of 0.575 M CuCl2 is diluted into 750 mL, what is the concentration of new solution?

Answer 1

Answer:

The answer is 0.228 M

Explanation:

To find the concentration of new solution we use the formula

$C_1V_1 = C_2V_2$

where

C1 is the concentration of the stock solution

V1 is the volume is the volume of the stock solution

C_2 is the concentration of the diluted solution

V2 is the volume of the diluted solution

Since we are finding the the concentration of new solution

$C_2 = \frac{C_1V_1}{V_2}$

From the question

C1 = 0.575 M

V1 = 298 mL

V2 = 750 mL

We have

$C_2 = \frac{0.575 \times 298}{750} \\ = 0.228466666...$

We have the final answer as

0.228 M

Hope this helps you