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Step2247 [10]
3 years ago
11

According to each substances heat of fusion, which of the items below requires more heat to be added per gram of substance to go

from solid to liquid?
silver
sulfur
water
lead
Chemistry
1 answer:
alexira [117]3 years ago
7 0

<u>Answer: </u>The correct answer is Silver.

<u>Explanation:</u>

Specific heat of fusion is defined as the amount of heat which is required to raise the temperature of 1 gram of a substance to 1°C. It is generally expressed in kJ/mol

We are required to find the substance which require more heat. For that we need to know the specific heat of all the substances.

The substance which have the highest specific heat, will require more heat.

The specific heat of the given substances are:

Silver = 11.3 kJ/mol

Sulfur = 1.7175 kJ/mol

Water = 5.98 kJ/mol

Lead = 4.799 kJ/mol

The specific heat of silver is the highest and hence, will require more heat.

Hence, the correct answer is silver.

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At T = 250 °C the reaction PCl5(g) PCl3(g) + Cl2(g) has an equilibrium constant in terms of pressures Kp = 2.15. (a) Suppose the
Ganezh [65]

Answer:

To the right

Explanation:

Step 1: Given data

  • Partial pressure of PCl₅ (pPCl₅) = 0.548 atm
  • Partial pressure of PCl₃ (pCl₃) = 0.780 atm
  • Partial pressure of Cl₂ (pCl₂) = 0.780 atm

Step 2: Write the balanced equation

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

Step 3: Calculate the pressure reaction quotient

Q_p = \frac{pPCl_3 \times pCl_2 }{pPCl_5} = \frac{0.780 \times 0.780 }{0.548} =1.11

Step 4: Determine whether the reaction proceeds to the right or to the left as equilibrium is approached

Since <em>Qp < Kp</em>, the reaction will proceed to the right to attain the equilibrium.

7 0
3 years ago
1.2 moles of (NH4)3PO3
Aleks04 [339]
1.2 moles of (nph4)3po3 is.......159.6 grams
3 0
3 years ago
How much heat does it take to melt 2.5 kg of lead when it is at its melting point (m.p. = 327.5°C; Hf = 2.04 × 104 J/kg)?
irinina [24]
1. the amount of heat that it would take would be :
5.1 x 10^4 J

2. I think the substance would be : Iron

3. the amount of heat required would be :
1.13 x 10^4 kJ

Hope this helps
6 0
3 years ago
Read 2 more answers
Balancing out Fe +h2O fe3O4 +H2
Katyanochek1 [597]
3Fe + 4H2O (yields) Fe3O4 + 4H2
4 0
3 years ago
The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos
Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

Explanation:

Mass of Earth =5.9\times 10^{21} tons

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth =5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g

Percentage of earth crust = 0.50%

Mass of earth crust = M

0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100

M=2.6762\times 10^{25} g

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

Si\%=\frac{m}{M}\times 100

27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100

m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

7 0
3 years ago
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