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Leni [432]
3 years ago
12

A sample of tin (II) chloride has a mass of 0.49 g. After heating, it has a mass of 0.41 g. 

Chemistry
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

16 percent

Explanation:

Just answered the question

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Find the value of 6 +<br>6 +<br>6 + 16 + vo​
AVprozaik [17]

Answer:

6

Explanation:

the value is 6 because its an even number

7 0
2 years ago
How fast is an electron travelling If it has a wavelength of 8.20 km?
Lemur [1.5K]

The electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

<h3>How to calculate velocity of an electron?</h3>

The velocity at which an electron travels can be calculated using the following formula:

λ = h/mv

Where;

  • H = Planck's constant
  • m = mass of electron
  • v = velocity of electron
  • λ = wavelength

  • Planck's constant (h) = 6.626 × 10−³⁴ J⋅s.
  • mass of electron (m) = 9.109 × 10−³¹ kg
  • wavelength = 8200m

8200 = 6.626×10−³⁴ / 9.109 × 10−³¹V

8200 = 7.3 × 10-⁴V

V = 8200 ÷ 7.3 × 10-⁴

V = 1.123 × 10⁷m/s

Therefore, the electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

Learn more about velocity at: brainly.com/question/13171879

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5 0
1 year ago
How many grams are there in 9.40*10^25 molecules of H2
IrinaVladis [17]

>4Dt. 1950 y fueron. 45Dys Imox x Na motu cues G.91 %10° mole cultes. 3) How many grams are there in 2.3 x 1024 atoms of silver? 2, 3x 10°tatoms x Imol.<

5 0
3 years ago
What is the mass of helium atom whose atomic weight is 4.003 g/mol?
tino4ka555 [31]

Answer:

Atoms He (Avogadro’s number) → Moles of He (molar mass of He) → Mass of He

• molar mass of He (from the periodic table) = 4.003 g/mol

• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole: 6.022 × 1023 He atoms in 1 mole of He

hope this is help full please mark me Brainliest

4 0
2 years ago
When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of the solution according to th
kipiarov [429]

The concentration of the sodium chloride would be 0.082 M

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the ratio of AgCl produced to NaCl required is 1:1.

Mole of 46.6 g AgCl produced = 46.6/143.32 = 0.325 moles

Equivalent mole of NaCl = 0.325 moles.

Molarity of 0.325 moles, 3.95 L NaCl = mole/volume = 0.325/3.95 = 0.082 M

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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3 0
1 year ago
Read 2 more answers
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