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2 years ago

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A sample of tin (II) chloride has a mass of 0.49 g. After heating, it has a mass of 0.41 g.

1 answer:

lyudmila [28]2 years ago

5 0

Answer:

16 percent

Explanation:

Just answered the question

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dexar [7]

Energy is stored in chemical bonds during photosynthesis.

During photosynthesis, the radiant energy from the sun is converted to chemical energy in carbohydrates.

Inorganic materials in the form of carbon dioxide and oxygen combine to form carbohydrates in the presence of radiant energy according to the equation below:

$6CO_2 + 6H_2O ---> C_6H_1_2O_6 + 6O_2$

The energy is thus, stored in chemical bonds in the carbohydrate and this is what is oxidized during respiration to release the locked energy.

More on photosynthesis can be found here: brainly.com/question/1388366

7 0

2 years ago

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Heat transfer between two substances is affected by specific heat and the chemical composition of the substances. state of matte

lesya [120]

Answer:

the answer is D

Explanation:

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2 years ago

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A car engine produces 604 kJ of mechanical energy from fuel capable of producing 2416 kJ of energy. The efficiency of the engine

Anna71 [15]

I think it’s 40% but I’m not sure

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3 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

2 years ago

Methane reacts with oxygen to produce carbon dioxide and water,What are the products? A. methane and water. B. oxygen and carbon

EleoNora [17]

D, carbon dioxide and water. Methane and oxygen PRODUCE carbon dioxide and water in their reaction.

3 0

3 years ago

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