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4 years ago

Zeros between a decimal point and a non zero number are _______ significant

1 answer:

6 0

They are indeed significant. This statement is true. The zero that is not significant is the one found before the first non-zero digit.

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In a ruby laser, an electron jumps from a higher energy level to a lower one. if the energy difference between the two levels is

Vaselesa [24]

The wavelength of the emitted photon is( $\lambda$ )= 690nm

<h3>How can we calculate the wavelength of the emitted photon?</h3>

To calculate the wavelength of the photon we are using the formula,

$\triangle E= \frac{h\times c}{\lambda}$

Or, $\lambda= \frac{h\times c}{\triangle E}$

We are given here,

$\triangle E$ = The energy difference between the two levels = 1. 8 ev= $1.8\times 1.6 \times 10^{-19}$ C.

h= Planck constant = $6.626\times 10^{-34}$ Js.

c= speed of light = $3\times10^8$ m/s.

We have to find the wavelength of the emitted photon = $\lambda$ m.

Therefore, we substitute the known parameters in the above equation, we can find that,

$\lambda= \frac{h\times c}{\triangle E}$

Or, $\lambda= \frac{6.626\times 10^{-34}\times 3\times 10^8}{1.8\times 1.6 \times 10^{-19}}$

Or, $\lambda= 690\times 10^{-9}$ m

Or, $\lambda$ =690 nm.

From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.

Learn more about ruby laser:

brainly.com/question/17245697

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8 0

2 years ago

A point charge q1 = 4.50 nC is located on the x-axis at x = 1.95 m , and a second point charge q2 = -6.80 nC is on the y-axis at

Vinvika [58]

Answer:

Explanation:

One charge is situated at x = 1.95 m . Second charge is situated at y = 1.00 m

These two charges are situated outside sphere as it has radius of .365 m with center at origin. So charge inside sphere = zero.

Applying Gauss's theorem

Flux through spherical surface = charge inside sphere / ε₀

= 0 / ε₀

= 0 Ans .

3 0

3 years ago

6.3 Calculate the current that flows through the element of a heater when the potential difference is 250V and the resistance of

ryzh [129]

Answer:

16.66

Explanation:

3 0

3 years ago

What two factors will make an object stable

galben [10]

The position of the centre of gravity of an object affects its stability. The lower the centre of gravity (G) is, the more stable the object. The higher it is the more likely the object is to topple over if it is pushed. Racing cars have really low centres of gravity so that they can corner rapidly without turning over.

Increasing the area of the base will also increase the stability of an object, the bigger the area the more stable the object. Rugby players will stand with their feet well apart if they are standing and expect to be tackled.

8 0

3 years ago

A cannon is fired straight up into the air. If the cannon ball comes back down to the launch point in 5 seconds, what was the ma

Nana76 [90]

Answer:

30.63 m

Explanation:

From the question given above, the following data were obtained:

Total time (T) spent by the ball in air = 5 s

Maximum height (h) =.?

Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:

Total time (T) spent by the ball in air = 5 s

Time (t) taken to reach the maximum height =.?

T = 2t

5 = 2t

Divide both side by 2

t = 5/2

t = 2.5 s

Thus, the time (t) taken to reach the maximum height is 2.5 s

Finally, we shall determine the maximum height reached by the ball as follow:

Time (t) taken to reach the maximum height = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

h = ½gt²

h = ½ × 9.8 × 2.5²

h = 4.9 × 6.25

h = 30.625 ≈ 30.63 m

Therefore, the maximum height reached by the cannon ball is 30.63 m

3 0

4 years ago