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Alona [7]
3 years ago
7

A 6-column table with 1 row. The first column labeled Number of Washers has entry 2. The second column labeled initial velocity

v subscript 1 (meters per second) has entry 0.13. The third column labeled final velocity v subscript 2 (meters per second) has entry 0.36. The fourth column labeled Time to travel 0.25 meters t subscript 1 (seconds) has entry 1.92. The fifth column labeled time to travel 0.5 meters t subscript 2 (seconds) has entry 2.61. The sixth column labeled Acceleration a = StartFraction (v subscript 2 minus v subscript 1) over (t subscript 2 minus t subscript 1) EndFraction (meters per second squared) has entry empty.
The acceleration of the car with the data in the table above would be
m/s2.

If the applied force were cut in half, what do you predict the acceleration would be?
m/s2
Physics
2 answers:
BigorU [14]3 years ago
6 0

Answer:

.33

.17

Explanation:

I just did the assignment

Sav [38]3 years ago
6 0

Answer:

.33 and .17

Explanation:

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marusya05 [52]

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3 0
3 years ago
a rocket with a mass of 4kg accelerates up from the ground at a rate of 20ft m/s^2, what is the drag force acting on the rocket
Maru [420]

The drag force acting on the rocket is 80N.

<h3>Give an explanation of drag force?</h3>

The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.

The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.

The drag force acting on the rocket F = ma

Given,

m = 4kg, a = 20ftm/s²

Substituting m and a values in the above formula,

The drag force acting on the rocket F = 4×20

The drag force acting on the rocket F = 80N.

To know more about drag force visit:

brainly.com/question/15144984

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8 0
2 years ago
What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is 5.90 x 10^5 K?
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<u>Answer:</u> The average kinetic energy of helium atoms is 1.222\times 10^{-17}J

<u>Explanation:</u>

To calculate the average kinetic energy of the atom, we use the equation:

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K = average kinetic energy = ?

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Putting values in above equation, we get:

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Hence, the average kinetic energy of helium atoms is 1.222\times 10^{-17}J

4 0
3 years ago
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