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Alona [7]
3 years ago
7

A 6-column table with 1 row. The first column labeled Number of Washers has entry 2. The second column labeled initial velocity

v subscript 1 (meters per second) has entry 0.13. The third column labeled final velocity v subscript 2 (meters per second) has entry 0.36. The fourth column labeled Time to travel 0.25 meters t subscript 1 (seconds) has entry 1.92. The fifth column labeled time to travel 0.5 meters t subscript 2 (seconds) has entry 2.61. The sixth column labeled Acceleration a = StartFraction (v subscript 2 minus v subscript 1) over (t subscript 2 minus t subscript 1) EndFraction (meters per second squared) has entry empty.
The acceleration of the car with the data in the table above would be
m/s2.

If the applied force were cut in half, what do you predict the acceleration would be?
m/s2
Physics
2 answers:
BigorU [14]3 years ago
6 0

Answer:

.33

.17

Explanation:

I just did the assignment

Sav [38]3 years ago
6 0

Answer:

.33 and .17

Explanation:

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A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
Sergeeva-Olga [200]

Answer:

ok what is the question

3 0
3 years ago
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Two identical masses are connected to two different flywheels that are initially stationary. Flywheel A is larger and has more m
inysia [295]

Answer:

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

c) True. Information is missing to perform the calculation

Explanation:

Let's consider solving this exercise before seeing the final statements.

We use Newton's second law Rotational

      τ = I α

     T r = I α

     T gR = I α

     Alf = T R / I (1)

     T = α I / R

Now let's use Newton's second law in the mass that descends

     W- T = m a

     a = (m g -T) / m

The two accelerations need related

     a = R α

    α = a / R

    a = (m g - α I / R) / m

    R α = g - α I /m R

    α (R + I / mR) = g

    α = g / R (1 + I / mR²)

We can see that the angular acceleration depends on the radius and the moments of inertia of the steering wheels, the mass is constant

Let's review the claims

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

b) False. Missing data for calculation

c) True. Information is missing to perform the calculation

d) False. There is a dependency if the radius and moment of inertia increases angular acceleration decreases

4 0
4 years ago
Which of the following would produce the most power?
Fantom [35]

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

But Energy = mgh

Substituting into the equation, we have

Power = \frac {mgh}{time}

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

Power = \frac {10*9.8*10}{5} = 490 Watts

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

6 0
3 years ago
suppose both the dog and the girl run at a speed of 2 m/s.Calculate both of there kinetic energies. kinetic energy of dog =
Andre45 [30]

Answer:

78

Explanation:

4 0
4 years ago
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The car's initial speed was 15 m / s and the distance the car travels before it comes to a complete stop after the driver applie
pentagon [3]

Initial speed of the car (u) = 15 m/s

Final speed of the car (v) = 0 m/s (Car comes to a complete stop after driver applies the brake)

Distance travelled by the car before it comes to halt (s) = 63 m

By using equation of motion, we get:

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\therefore Acceleration of the car (a) = -1.78 m/s²

Magnitude of the car's acceleration (|a|) = 1.78 m/s²

5 0
3 years ago
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