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Studentka2010 [4]
3 years ago
10

If you know the answer please answer the following question down in the picture below.

Physics
2 answers:
otez555 [7]3 years ago
7 0
Arrows point away from north and forward south, and Field lines loop around the magnet starting at the North Pole and ending at the South Pole.

I think this is the correct answer, not necessarily sure though.
netineya [11]3 years ago
6 0

Answer:

the answer is C

I hope I helped (◍•ᴗ•◍)❤

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How much kinetic energy does a care 1000 kg car moving at 7 m/s have?
aalyn [17]
Hey there!

<span>How much kinetic energy does a care 1000 kg car moving at 7 m/s have?

Answer:
</span><span>A. 24500 J

Hope this helps
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5 0
3 years ago
What voltage is required to move 6A through 5Ω?
Scorpion4ik [409]
30 volts

E= IxR

See ohms law calculator image below

7 0
3 years ago
Which of the following is an example of charging by friction?
taurus [48]

Answer: where is the examples?

Explanation:

6 0
3 years ago
Read 2 more answers
Which one?? please someone quick!​
LiRa [457]

Answer:

i think its second law of motion.

Explanation:

4 0
3 years ago
Read 2 more answers
A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c
sergiy2304 [10]

Answer:

Part a)

a_{hanger} = g - \frac{T}{m}

Part b)

a_{cart} = \frac{T}{M}

Part c)

a = \frac{mg}{M + m}

Part d)

a = 1.35 m/s^2

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

mg - T = ma

so we have

a_{hanger} = g - \frac{T}{m}

Part b)

now for car that is rolling on the floor the net force is given as

F = Ma

T = Ma

a_{cart} = \frac{T}{M}

Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

T = Ma

mg - Ma = ma

a = \frac{mg}{M + m}

Part d)

now we know that

M = 2.40 kg

m = 0.50 kg

so we will have

a = \frac{0.50(9.81)}{2.40 + 0.50}

a = 1.35 m/s^2

6 0
3 years ago
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