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Studentka2010 [4]

3 years ago

10

If you know the answer please answer the following question down in the picture below.

2 answers:

otez555 [7]3 years ago

7 0

Arrows point away from north and forward south, and Field lines loop around the magnet starting at the North Pole and ending at the South Pole.

I think this is the correct answer, not necessarily sure though.

netineya [11]3 years ago

6 0

Answer:

the answer is C

I hope I helped (◍•ᴗ•◍)❤

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How much kinetic energy does a care 1000 kg car moving at 7 m/s have?

aalyn [17]

Hey there!

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Answer:
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3 years ago

What voltage is required to move 6A through 5Ω?

Scorpion4ik [409]

30 volts

E= IxR

See ohms law calculator image below

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3 years ago

Which of the following is an example of charging by friction?

taurus [48]

Answer: where is the examples?

Explanation:

6 0

3 years ago

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Which one?? please someone quick!

LiRa [457]

Answer:

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Explanation:

4 0

3 years ago

Read 2 more answers

A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c

sergiy2304 [10]

Answer:

Part a)

$a_{hanger} = g - \frac{T}{m}$

Part b)

$a_{cart} = \frac{T}{M}$

Part c)

$a = \frac{mg}{M + m}$

Part d)

$a = 1.35 m/s^2$

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

$mg - T = ma$

so we have

$a_{hanger} = g - \frac{T}{m}$

Part b)

now for car that is rolling on the floor the net force is given as

$F = Ma$

$T = Ma$

$a_{cart} = \frac{T}{M}$

Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

$T = Ma$

$mg - Ma = ma$

$a = \frac{mg}{M + m}$

Part d)

now we know that

M = 2.40 kg

m = 0.50 kg

so we will have

$a = \frac{0.50(9.81)}{2.40 + 0.50}$

$a = 1.35 m/s^2$

6 0

3 years ago