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erastova [34]
2 years ago
8

Which one?? please someone quick!​

Physics
2 answers:
LiRa [457]2 years ago
4 0

Answer:

i think its second law of motion.

Explanation:

defon2 years ago
3 0

Answer:

it’s the second law

Explanation:

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A pilot drops a bomb from a plane flying horizontally with constant velocity. When the bomb hits the ground, the horizontal loca
polet [3.4K]

Answer: The horizontal location of the plane will BE OVER THE BOMB

Explanation:

As soon as the bomb was dropped, the bomb will fall under gravity (free fall) and the location of the plane continues to increase horizontally till the bomb reaches the ground which is a falling distance to be travelled by the bomb at 9.8m/s²

8 0
3 years ago
A person drives 20 miles north and 45 miles east. What is the angle of the resultant straight to their destination?
Alex787 [66]
Let us take east and north as the positive x and y-axes should the motion be plotted in a cartesian plane. Thus, the x value is 45 miles and the y value is 20. The tangent of an angle is equal to the ratio of y to x.

   tanθ = y / x

Substituting,

   tanθ = 20/45 = 0.44

The value of θ is 23.96°.
7 0
2 years ago
What happens to its surface temperature as a star changes color from red to blue
MAVERICK [17]
The surface temperature of the star increases when it changes its colour changes from red to blue.
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The given series is the temperature decreasing order of stars. Now our sun is considered as a yellow star.
5 0
3 years ago
Two charges, Q1 and Q2, are separated by 6·cm. The repulsive force between them is 25·N. In each case below, find the force betw
Misha Larkins [42]

Answer:

a) 5 N b) 225 N c) 5 N

Explanation:

a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of  the distance between them, acting along  the  line that joins the charges, as follows:

F₁₂ = K Q₁ Q₂ / r₁₂²

So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N

b) If we reduce the distance, from r, to r/3, as the  factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.

So, we will have F₁₂ = 9. 25 N = 225 N

c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:

F₁₂ = 25 N .1/5 = 5 N

3 0
3 years ago
Two trains A and B of length 400 m each are moving on two parallel tracks with
Vinvika [58]

<u>Answer:</u>

<em>The initial distance between the trains is 1450 m. </em>

<u>Explanation:</u>

In the question two trains are of equal length 400 m and moves at a uniform speed of 72 km/h. train A is moving ahead of train B. If the train B has to overtake train A it should accelerate.

Train B’s acceleration  is 1m/s^2   and it accelerated for 50 seconds.

<em>a=1 m/s^2</em>

<em>t=50 s </em>

<em>initial speed u=72km/h </em>

<em>we have to convert this speed into m/s  </em>

<em>u=72 \times 5/18=20 m/s</em>

<em>Distance covered in accelerating phase  S=ut+1/2  at^2  </em>

<em>=20 \times 50+1/2 \times 1 \times 50^2</em>

<em>=1000+1250=2250 m </em>

If  a train is just behind another, the distance covered by the train located behind during overtaking phase will be equal to the sum of the lengths of the trains.

<em>Here length of train A+length of train B=400+400=800 m</em>

<em>Hence the initial distance between the trains = 2250-800=1450 m</em>

6 0
3 years ago
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