So you can have a understanding of what you are doing and figure out your overall goal
We have that the time in seconds, minutes, and hours is



From the Question we are told that
Velocity 
Distance 
Generally the equation for the Time is mathematically given as
Therefore


And


For more information on this visit
brainly.com/question/12319416?referrer=searchResults
If,

then, with 3x time t, (suppose, new distance is h)




Therefore, new distance h will be 9 times bigger than distance d.
answer: c
Velocity is define as how fast an object is moving, and in what direction, it is a vector quantity, meaning velocity has both magnitude and direction. Anything goes to the left is negative, and anything goes to the right is positive.
a. Direction from east to west, given distance 11.5 meters, and time of 7.10 s
V = displacement/time V = -11.5/7.10 S V = -1.62 m/s (going left)
b. Joaquin reaches his original position. Displacement is now zero.
Velocity of the lawnmower is equal to "zero" but if we calculate for the average speed of the lawn, you just have to add the distance covered and the time it take to go back at the original position or point of origin