where, E^{o} (Ag+/Ag) = std. reduction potential of Ag+ = 0.7994 v
and Sn2+/Sn = std. reduction potential of Sn2+ = -0.14 v
Thus, E^{o}cell = 0.7994v - (-0.14v) = 0.9394 v
Now, ΔG^{o} = -nF
,
where, n = number of electrons = 2
F = Faraday's constant = 96500 C
∴ΔG^{o} = 2 X 96500 X 0.9394 = -1.18 X
Now, using Nernst's Equation we have,
![[tex]E_{cell} = 0.9394 - \frac{2.303X298}{2X96500}log \frac{0.0115}{ 3.5^{2} }](https://tex.z-dn.net/?f=%20%5Btex%5DE_%7Bcell%7D%20%3D%200.9394%20-%20%5Cfrac%7B2.303X298%7D%7B2X96500%7Dlog%20%5Cfrac%7B0.0115%7D%7B%203.5%5E%7B2%7D%20%7D%20)
E_{cell} = 0.9765 v
Finally, ΔG = -nFE = -2 X 96500 X 0.9765 = -1.88 X
Answer:
- A ball does not move unlesss you kick it and it rolls aways
- a car stays still and is not in motion, unless you start the engine
- a pencil stays still on a table, it moves when you pick it up off the table
Explanation:
Answer:
it's a metel
Explanation:
as far as it can conduct electricity.
it's not a metal if it can't except it it's a metalloids
Answer:
CH3COOH will be the acid, because it is the stronger acid.
Explanation:
When an acid deprotonates in a solution, an equilibrium reaction will occur between the protonated form and the deprotonated form (conjugate base) of it. The equilibrium is characterized by the value of Ka, the equilibrium constant, which is the multiplication of the concentration of the products divided by the concentration of the acid.
As higher is the value of Ka, more acid is deprotonated, and stronger will be the acid. The value of pKa = -logKa, and so, as higher is the Ka, as low is the pKa. Thus, strong acids have low pKa values.
In the reaction of CH3COOH and H2O, the first one has a low value of pKa, so it is a strong acid. The water is a substance that can work as an acid or as a base, and, because of the other substance is a strong acid, it works as a base.
