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zhenek [66]
3 years ago
8

As student used a pen to draw a line across a piece of chromatography paper. he then placed a sample of dye on the drawn line fo

r analysis . is the student doing the right thing? why?​
Chemistry
1 answer:
AleksAgata [21]3 years ago
3 0

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

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Which element must be present in an avid
Yuliya22 [10]
WHat? May you please rephrase your question? I think you meant in an organic compound? The answer to that would be CARBON.
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3 years ago
Identify the type of reaction. Complete the equations with the correct reactants then balance each equation.
tester [92]

Answer:

The answer to your question is below

Explanation:

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4 years ago
Why do we research<br> before conducting our<br> experiment?
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What occurs when a magnesium atom becomes a magnesium ion
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Read 2 more answers
For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at
maw [93]

Answer:

2.55*10^{11

Explanation:

Equation for the heterogeneous system is given as:

2A_{(aq)}  + 3 B_{(g)} + C_{(l)}      ⇄      2D_{(s)}    +     3E_{(g)}

The concentrations and pressures at equilibrium  are:

[A] = 9.68*10^{-2}M

P_B = 9.54*10^3Pa

[C]=14.64M

[D]=10.11M

P_E=9.56*10^4torr

If we convert both pressure into bar; we have:

P_B = 9.54*10^3Pa

P_B = (9.54*10^3)*\frac{1}{10^5} bar

P_B=9.54*10^{-2}bar

P_E=9.56*10^4torr

1 torr = 0.001333 bar

9.54*10^4 *0.001333 = 127.5 bar

K=\frac{[P_E]^3}{[A]^2[P_B]^3}

K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}

K=2.55*10^{11

3 0
3 years ago
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