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Tamiku [17]
3 years ago
6

If a “sample” of pennies contained 75 heads and 25 tails, how many half‐lives would have passed since the “sample” formed. Expla

in your answer.
If a “sample” of pennies contained 25 heads and 75 tails, how many half‐lives would have passed since the “sample” formed. Explain your answer.

Please help, our teacher teaches nothing and we get random work with no context! This is the only question our whole (honors) class doesn't understand.
Chemistry
1 answer:
finlep [7]3 years ago
8 0
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ANSWER THESE 5 MULTPLE CHOICE QUESTIONS!!! <br> I'LL GIVE 30 POINTS AND A BRAINIEST:)
Artemon [7]

Answer:

1. B

2.C

3.D

4.Sorry don't this one :(

5.A

Explanation:

please give me at least 20 points ❤

7 0
3 years ago
A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrea
Maksim231197 [3]

Answer:

82.4 s

Explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s

8 0
1 year ago
Calculate the volume occupied by 272g
cupoosta [38]

The answer for the following problem is mentioned below.

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

Explanation:

Given:

mass of methane(CH_{4}) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of  methane(CH_{4}) = 16.0​  grams

We know;

According to the ideal gas equation,

<u><em>P × V = n × R × T</em></u>

here,

n = m÷M

n =272 ÷ 16

<u><em>n = 17 moles</em></u>

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

<u><em></em></u>

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6 0
3 years ago
X2o3 express you answer as a whole number
kobusy [5.1K]
 <span>2.40 - 1.68 =0.72 g of oxigen 
moles = 0.72/16 g/mol=0.045 

moles x = 1.68/ 55.9=0.03 

0.03/0.03 = 1 = x 
0.045 / 0.03 = 1.5 = O 

to get whole numbers multiply by 2 

x2O3 

X2O3 +3 CO = 2 X + 3 CO2</span>
4 0
4 years ago
PLEASEEEE HELP MEE!
Ugo [173]

Answer:

2nd option

Explanation:

7 0
3 years ago
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