The total displacement of the toy car at the given positions is 0.
The given parameters;
- <em>First displacement of the car, = 5 cm left</em>
- <em>Second displacement of the car, = 8 cm right</em>
- <em>Third displacement of the car, = 3 cm to the left</em>
The total displacement of the car is calculated as follows;
- <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
- <em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

Thus, the total displacement of the toy car at the given positions is 0.
Learn more about displacement here: brainly.com/question/18158577
Explanation:
Fe₂O₃ + CO → Fe₃O₄ + CO₂
Balancing the equation above, we can derive simple mathematical equations that are very easy to solve.
aFe₂O₃ + bCO → cFe₃O₄ + dCO₂
a,b,c and d are the coefficients needed to balance the equation above;
Conserving Fe; 2a = 3c
O: 3a + b = 4c + 2d
C: b = d
let a = 1;
c = 
Since b = d
3a + d = 4c + 2d
3a = 4c + 2d - d
3a = 4c + d
a = 1, c = 
3 = 4 x
+ d
d = 
b = 
multiplying a, b, c and d by 3:
a = 3 b = 1 c = 2 and d = 1
3Fe₂O₃ + CO → 2Fe₃O₄ + CO₂
Learn more:
Balanced equation brainly.com/question/2612756
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A quadrilateral with only one pair of parallel sides.
<span>a small carpal bone in the base of the hand, articulating with the metacarpal of the index finger.
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All you would do is for a, 10 times 2 is 20 so it would be 20-dB
For b, 10 times 4 is 40 so it would be 40-dB
<span>For c, 10 times 8 is 80 so it would be 80-dB</span>