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3 years ago

Simplify 3^-9 over 3^-12

Mathematics

2 answers:

8_murik_8 [283]3 years ago

7 0

It would be simplified to 27

Shkiper50 [21]3 years ago

3 0

Answer:

B - 1/(3^21)

Step-by-step explanation:

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What is the area of the composite figure shown

Greeley [361]

So, We Know That The Figure Shown Is A Square. So, We Need To Find The Area:
70*70 = 4900.

So, We Have:
490 - (Area Of The Triangle) = A

So, Lets Find The Area Of The Triangle.

(35*70)/2
Well, 35*70 = 2450.
So:
2450/2 = 1225.

Now, Do:

4900 - 1225 = A

4900 - 1225 = 3675

So:
3675cm² = A

8 0

2 years ago

Declan ran 500 meters in 5 minutes . calculate the unit rate

SIZIF [17.4K]

Answer:

100 meters in 1 minute

Step-by-step explanation:

500/5=100

5 0

3 years ago

Read 2 more answers

Determine the ratio in which the point (–6, m) divides the join of A(–3, –1) and B(–8, 9). Also, find the value of m.

PSYCHO15rus [73]

Answer:

Ratio = 3 : 2 and value of m = 5.

Step-by-step explanation:

We are given the end points ( -3,-1 ) and ( -8,9 ) of a line and a point P = ( -6,m ) divides this line in a particular ratio.

Let us assume that it cuts the line in k : 1 ratio.

Then, the co-ordinates of P = $( \frac{-8k-3}{k+1},\frac{9k-1}{k+1} )$ .

But, $\frac{-8k-3}{k+1}$ = -6

i.e. -8k-3 = -6k-6

i.e. -2k = -3

i.e. $k = \frac{3}{2}$

So, the ratio is k : 1 i.e $\frac{3}{2} : 1$ i.e. 3 : 2.

Hence, the ratio in which P divides the line is 3 : 2.

Also, $\frac{9k-1}{k+1}$ = m where $k = \frac{3}{2}$

i.e. m = $\frac{\frac{9 \times 3}{2}-1}{\frac{3}{2}-1}$

i.e. m = $\frac{27-2}{3+2}$

i.e. m = $\frac{25}{5}$

i.e. m = 5.

Hence, the value of m is 5.

4 0

2 years ago

Read 2 more answers

Write the ratio of the area of a circle with radius r to the circumference of the same circle

Goshia [24]

Answer:

$\frac{r}{2\pi r} =\frac{1}{2\pi }$

Step-by-step explanation:

A ratio is a comparison of two quantities and can be written in several forms including fractions. It is most commonly written in fraction form or a:b.

To write a ratio, we count the number of each quantity we are comparing or use the variable for that quantity. We write radius:circumference. Recall, the circumference of a circle can be found using $\pi d$ or $2\pi r$ .