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harkovskaia [24]

2 years ago

15

Hydrogen can be found in many things. It cannot be broken down to create something else. An example of something like hydrogen i

s oxygen. We call things like hydrogen or oxygen _ .

1 answer:

KiRa [710]2 years ago

6 0

Answer:

matter im pretty sure sorry if its wrong

Explanation:

based on the property of conserving matter, matter can not be created or destroyed

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How many moles is 2.2 x 1023 atoms of Fe?

kow [346]

Answer:

it's 3.77 moles

Explanation:

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2 years ago

Examples of solid mixtures

elixir [45]

Salad, a bag of different colored pebbles or sand, etc

6 0

2 years ago

if a leaf falls from a tree we assume that it is in free fall and not affected by air resistance, how many force vectors does th

lakkis [162]

Just the force of gravity down.

7 0

2 years ago

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.

patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of $NH_{3}$ is as follows:.

$2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)$

And, initially only $NH_{3}$ is present.

The given data is as follows.

$P_{NH_{3}}$ = 2.3 atm at equilibrium

$P_{H_{2}} = 3 \times P_{N_{2}}$ = 0.69 atm

Therefore,

$P_{N_{2}} = \frac{0.69 atm}{3}$

= 0.23 aatm

So, $P_{NH_{3}}$ = 2.3 - 2(0.23)

= 1.84 atm

Now, expression for $K_{p}$ will be as follows.

$K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}$

$K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}$

= $\frac{0.23 \times 0.33}{3.39}$

= 0.0224

or, $K_{p} = 2.2 \times 10^{-2}$

Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is $2.2 \times 10^{-2}$ .

6 0

3 years ago

A runner runs 4339 ft in 7.45 minutes. What is the runner's average speed in miles per hou 6.62 mi/hr O 0.110 mi/hr 6.618 mi/h e

slavikrds [6]

<u>Answer:</u> The average speed of the runner is 6.618 miles/hr

<u>Explanation:</u>

Average speed is defined as the ratio of total distance traveled to the total time taken.

To calculate the average speed of the runner, we use the equation:

$\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}$

We are given:

Distance traveled = 4339 ft

Time taken = 7.45 mins

Putting values in above equation, we get:

$\text{Average speed of runner}=\frac{4330ft}{7.45min}=582.42ft/min$

To convert the speed into miles per hour, we use the conversion factors:

1 mile = 5280 ft

1 hr = 60 mins

Converting the speed into miles per hour, we get:

$\Rightarrow \frac{528.42ft}{min}\times (\frac{1miles}{5280ft})\times (\frac{60min}{1hr})\\\\\Rightarrow 6.618mil/hr$

Hence, the average speed of the runner is 6.618 miles/hr

6 0

2 years ago