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harkovskaia [24]
3 years ago
15

Hydrogen can be found in many things. It cannot be broken down to create something else. An example of something like hydrogen i

s oxygen. We call things like hydrogen or oxygen _ .
Chemistry
1 answer:
KiRa [710]3 years ago
6 0

Answer:

matter im pretty sure sorry if its wrong

Explanation:

based on the property of conserving matter, matter can not be created or destroyed

You might be interested in
Determine the identity of the daughter nuclide from the positron emission of 6832ge. determine the identity of the daughter nucl
RideAnS [48]

Answer:- The daughter nuclide is Gallium with atomic number 31 and mass number 68.

Explanations:- Positron emission is also known as beta plus decay. In this type of radioactive decay in which a proton changes into neutron and a positron and electron neutrino are released.

As the proton changes into neutron, mass number remains same but the atomic number decreases by one unit.

The given element is Ge with atomic number 32 and mass number 68. Mass number decreases by one unit means the atomic number of the daughter nuclide would be 31 and it is Gallium.

The equation could be written as:

_3_2Ge^6^8\rightarrow _3_1Ga^6^8+e^++v_e

7 0
3 years ago
Calculate the Molarity of 89.94 g NaCl is dissolved in 1249 mL of solution.
tino4ka555 [31]

Answer:

The molarity of the solution is 1, 23 M.

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

89,94 g ---------x= (89,94 g x 1 mol NaCl)/58, 5 g= 1,54 mol NaCl

1249 ml solution------ 1,54 mol NaCl

1000ml solution------x= (1000ml solutionx 1,54 mol NaCl)/1249 ml solution

x=1,23 mol NaCl---> The solution is 1, 23 molar (1,23 M)

7 0
3 years ago
suppose that two hydroxides, moh and m′ (oh)2, both have a ksp of 1.39 × 10−12 and that initially both cations are present in a
11Alexandr11 [23.1K]

When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>

Equation :

MOH (s)  ⇄ M⁺ (aq)  ₊ OH⁻(aq)

Ksp = [M⁺] [OH⁻]

Ksp = 1.39×10⁻¹² and [M⁺] = 0.001M

∴ 1.39×10⁻¹² = (0.001M) [OH⁻]

[OH⁻] =  1.004×10⁻¹⁹M

pOH = -log [OH⁻] =  11.9

pH = 14 - pOH

= 14 - 11.9

<u>pH = 2.1</u>

To learn more about solubility equilibrium ;

https://brainly.in/question/9213521

#SPJ4

8 0
2 years ago
A mixture of N2, O2, and Ar has mole fractions of 0.25, 0.65, and 0.10, respectively. What is the pressure of N2 if the total pr
s344n2d4d5 [400]

Answer:

Partial pressure of nitrogen gas is 0.98 bar.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.

P=p_{N_2}+p_{O_2}+p_{Ar}

p_{N_2}=P\times \chi_{N_2}

p_{O_2}=P\times \chi_{O_2}

p_{Ar}=P\times \chi_{Ar}

where,

P = total pressure = 3.9 bar

p_{N_2} = partial pressure of nitrogen gas  

p_{O_2} = partial pressure of oxygen gas  

p_{Ar} = partial pressure of argon gases  

\chi_{N_2} = Mole fraction of nitrogen gas  = 0.25

\chi_{O_2} = Mole fraction of oxygen gas  = 0.65

\chi_{Ar} = Mole fraction of argon gases = 0.10

Partial pressure of nitrogen gas :

p_{N_2}=P\times \chi_{N_2}=3.9 bar\times 0.25 =0.98 bar

Partial pressure of oxygen gas :

p_{N_2}=P\times \chi_{O_2}=3.9 bar\times 0.65=2.54 bar

Partial pressure of argon gas :

p_{N_2}=P\times \chi_{Ar}=3.9 bar\times 0.10=0.39 bar

7 0
4 years ago
Plz help me asap even faster then asap
iren2701 [21]

Answer:

The answer is D.8 sulfer atoms and 16 oxygen atoms

Explanation:

3 0
3 years ago
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