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3 years ago

What is the ratio of hydrogen atoms to oxygen atoms in a water molecule?

2 answers:

6 0

2 hydrogen molecules to one oxygen molecule
Remember by H2O since O doesn’t have a number after it you know there is only one oxygen molecule

ArbitrLikvidat [17]3 years ago

5 0

Answer:

The ratio of hydrogen atoms to oxygen atoms is 2 to 1.

Explanation:

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A student reports the following measurements for a set of pennies: 102.0mL, 91.0 g. What is the density of the pennies.

zysi [14]

Answer:

V = 102.0 ml

m = 91.0 ml

density = ...?

density = m / V

= 91.0 / 102.0

= 0.89215 g/ml

7 0

3 years ago

ACFrOgDjZVP5d1mO2l6HAtPZQNnbFRq674g04E7uZadqJMPc4VbhdTIEDCWBeh3xfw9BrKkfHHEN4nxe9NVglsb9N8D49CjxvxHYw3L93m4wO6SY5SwKQYMk-2zzHtGz

Dmitrij [34]

Answer:

No hay resultados para ACFrOgDjZVP5d1mO2l6HAtPZQNnbFRq674g04E7uZadqJMPc4VbhdTIEDCWBeh3xfw9BrKkfHHEN4nxe9NVglsb9N8D49CjxvxHYw3L93m4wO6SY5SwKQYMk-2zzHtGzerun1Uh9k-mpxFw9D3I1.pdf

Explanation:

hablemos por g mail

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3 years ago

Consider the formation of hcn by the reaction of nacn (sodium cyanide) with an acid such as h2so4 (sulfuric acid): 2nacn(s)+h2so

Artemon [7]

2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)

The molar ratio between NaCN : HCN is 2:2 or 1:1

Mass of HCN = 16.7 g

Molar mass of HCN = 1 + 12 + 14 = 27 g/mol

Molar mass of NaCN = 49 g/mol

Therefore, the mass of NaCN is

16.7 g of HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN

Therefore, 30.3 grams of NaCN gives the lethal dose in the room.

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3 years ago

Read 2 more answers

The sum of pH and pOH for any aqueous solution equals .

Vsevolod [243]

Answer:

pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7. Thus the sum of pH and pOH is 14

Explanation:

6 0

3 years ago

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago