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GrogVix [38]
3 years ago
7

Due to friction a body A gets electrified. It looses 200 electrons to another body B. Find the charge acquired by the bodies A a

nd B.
Physics
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

Explanation:

.it looses 200 electrons to another body b.fund the charge acquired b… ... 200 electrons to another body b.fund the charge acquired by the bodies a and b ... The line current is 5 A. Calculate the value of each resistor

Hope this helps! Please mark me as brainlyest!? :D

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A crate is acted upon by a net force of 100N. An acceleration of 5.0 m/s^2 results. What is the rate of the crate?
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Is there any other information given? I don't think you can solve this without a time
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A sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?
Alja [10]

Answer:

887.1Hz

Explanation:

Given parameters:

Speed of sound wave  = 330m/s

Wavelength  = 0.372m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

             Speed  = Frequency x wavelength

            330  = Frequency x 0.372

   Frequency  = 887.1Hz

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3 years ago
Is mercury a terrestrial or gaseous planet
liraira [26]

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8 0
3 years ago
Sound waves can travel through which mediums?
aksik [14]

Answer:

B. Solids, liquids, and gases.

Explanation:

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5 0
3 years ago
if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

4 0
3 years ago
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