Answer:
1.811 g
Explanation:
The computation of the mass need to use to make the solution is shown below:
We know that molarity is

So,


= 0.031 moles
Now

where,
The Molecular weight of NaCl is 58.44 g/mole
And, the moles are 0.031 moles
So, the mass of NaCL is

= 1.811 g
We simply applied the above formulas
Answer:
I would try but i just need points good luck tho
Answer:
B
Explanation:
Brainly Patrol ima stop you here
Here we have to choose the molecule which can generate ion-dipole interaction with ammonia.
The NH₃ will have ion dipole interaction only with b) NaOH.
a) The OCl₂ molecule is highly unstable and remains in a linear state as shown in the figure.
b) The NaOH is purely an ionic compound. There is one lone pair of electron on the nitrogen (N) atom of ammonia and also the N-H bond has dipole moment. Now among the given molecules only NaOH is ionic in nature which remains as Na⁺ and OH⁻. Thus we can expect an ion-dipole interaction between these molecules, it is shown in the figure.
c) SiO₂ is purely an covalent compound the structure is shown in the figure.
d) Methyl iodide (CH₃I) is also a covalent compound.
e) The butanol (C₄H₉OH) is a covalent compound.
So we may expect only ion-dipole interaction with b) NaOH.