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4 years ago

Solve for x: -5/6(8+-5/3x)=-10

Mathematics

2 answers:

EleoNora [17]4 years ago

7 0

Answer:

Step-by-step explanation:

ln(10^(3x-8)) = ln(2^(5-x))

[3x-8]ln(10) = [5-x]ln(2)

[3x-8]/[5-x] = ln(2)/ln(10)

(3*ln(10))x - 8*ln(10) = (5*ln(2)) - ln2*x

(3*ln(10))x + ln2*x = 8*ln(10) + (5*ln(2))

x(3*ln(10) + ln2) = 8*ln(10) + (5*ln(2))

7.6x = 21.886

x=2.88

Anon25 [30]4 years ago

6 0

X=-2 2/5
X=-2.4
X=-12/5

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The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

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Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

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$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

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$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

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$P(A \cup B) =0.4 +0.8-0.2 =1.0$

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The intersection between the set A and B is the element c so then we have this:

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Step-by-step explanation:

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Answered by GAUTHMATH

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