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3 years ago

If 52 is 130% of a number, is the number greater then or less the 52? Explain

2 answers:

6 0

The number must be less than 52 as is everything over 101%.

A percentage is just a fraction where the number to the left of the sign, let's say 'x', is placed in the numerator above 100 (example: x/100) = x%.

52 / 130% = 52 / 1.3 = 40

olga_2 [115]3 years ago

3 0

X= a number

If 52 is 130% of a number, then we multiply the unknown number by 130%.

x * 130%= 52
convert % to decimal (130%÷100)

1.3x= 52
divide both sides by 1.3

x= 40

ANSWER: The unknown number is 40, so it is less than 52. We multiply the unknown number by 130% to equal 52.

Hope this helps! :)

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2 years ago

I am thinking of two numbers. The sum of the two is 10 and the difference is 2

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Answer:

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2 years ago

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8 0

3 years ago

Read 2 more answers

Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s

vivado [14]

Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.

The estimate and the sample size are given by:

$\pi = 0.36, n = 100$ .

Then the bounds of the interval are:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.2364$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.4836$

The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago

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Anna71 [15]

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3 years ago

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