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densk [106]
4 years ago
12

given two continuous time signals x(t) and h(t), if their convultion is denoted by y(t) , then the convultion of x(t-1) and h(t+

1) is
Engineering
1 answer:
goldenfox [79]4 years ago
3 0

Answer:

y(t)=h(t+1)*x(t-1)

Explanation:

Ourput is show time delaying

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Automotive System. A group of related parts that perform a specific function. Body and Chassis System. Body, frame, suspension, steering, braking which support, stop and enclose the parts of the car.
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A ball is dropped from rest from the top of a cliff that is 30 m high. From ground
trasher [3.6K]

The distance below the top of the cliff that the two balls cross paths is 7.53 meters.

<u>Given the following data:</u>

  • Initial velocity = 0 m/s (since the ball is dropped from rest).
  • Height = 30 meters.

<u>Scientific data:</u>

  • Acceleration due to gravity (a) = 9.8 m/s^2.

To determine how far (distance) below the top of the cliff that the two balls cross paths, we would apply the third equation of motion.

<h3>How to calculate the velocity.</h3>

Mathematically, the third equation of motion is given by this formula:

V^2 = U^2 +2aS

<u>Where:</u>

  • V is the final velocity.
  • U is the initial velocity.
  • a is the acceleration.
  • S is the distance covered.

Substituting the parameters into the formula, we have;

V^2 = 0^2 +2(9.8) \times 30\\\\V^2 = 588\\\\V=\sqrt{588}

V = 24.25 m/s.

<u>Note:</u> The final velocity of the first ball becomes the initial velocity of the second ball.

The time at which the two balls meet is calculated as:

Time = \frac{S}{U} \\\\Time = \frac{30}{24.25}

Time = 1.24 seconds.

The position of the ball when it is dropped from the cliff is calculated as:

y_1 = h-\frac{1}{2} at^2\\\\y_1 = 30-\frac{1}{2} \times 9.8 \times 1.24^2\\\\y_1 = 30-7.53\\\\y_1=22.47\;meters

Lastly, the distance below the top of the cliff is calculated as:

Distance = 30-22.47

Distance = 7.53 meters.

Read more on distance here: brainly.com/question/10545161

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A) Gravity attracts horizontally downwards the weight of any object such a building or a part of building. (True / False)
PtichkaEL [24]

Answer:

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