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poizon [28]
3 years ago
7

A 6-pole, 50 Hz squirrel cage induction motor has rotor resistance and standstill reactance referred to stator of 0.2 ohm and 1

ohm per phase, respectively. With rated voltage and rated frequency it runs at full load with 4 % slip. Neglect stator resistance and rotational losses. Determine the operating speed of the motor, when the stator voltage impressed is reduced to 0.707 times the rated voltage, frequency remaining the same, if (a) the load torque remains constant at the rated motor (b) the load is of fan-type having rated torque at rated speed.

Engineering
1 answer:
aalyn [17]3 years ago
5 0

Answer:

Explanation:

Find attach the solution

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A manager has a list of items that have been sorted according to an item ID. Some of them are duplicates. She wants to add a cod
ruslelena [56]

Answer:

The solution code is written in Python:

  1. items = [{"id": 37697, "code": ""},{"id": 37698, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""}, {"id": 37699, "code": ""},
  2. {"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37699, "code": ""},{"id": 37700, "code": ""} ]
  3. items[0]["code"] = 1
  4. for i in range(1, len(items)):
  5.    if(items[i]["id"] == items[i-1]["id"]):
  6.        items[i]["code"] = items[i-1]["code"] + 1
  7.    else:
  8.        items[i]["code"] = 1
  9. print(items)

Explanation:

Firstly, let's create a list of dictionary objects. Each object holds an id and a code (Line 1-2). Please note all the code is initialized with zero at the first beginning.

Next, we can assign 1 to the <em>code</em> property of items[0] (Line 4).

Next, we traverse through the items list started from the second element (Line 6). We set an if condition to check if the current item's id is equal to the previous item (Line 7). If so, we assign the previous item's code + 1 to the current item's code (Line 8). If not, we assign 1 to the current item's code (Line 10).

At last, we print out the item (Line 12) and we shall get

[{'id': 37697, 'code': 1}, {'id': 37698, 'code': 1}, {'id': 37699, 'code': 1}, {'id': 37699, 'code': 2}, {'id': 37699, 'code': 3}, {'id': 37699, 'code': 4}, {'id': 37699, 'code': 5}, {'id': 37699, 'code': 6}, {'id': 37700, 'code': 1}]

 

6 0
3 years ago
Kim is working on the cost estimate and feasible design options for a building. Which stage of a construction plan is Kim workin
melisa1 [442]
Aye she suenebaiaksj
8 0
3 years ago
one number is 11 more than another number. find the two number if three times the larger number exceeds four times the smaller n
vaieri [72.5K]

Answer:

a = 40

b = 29

Explanation:

Give a place holder for the numbers that we don't know.

Lets call the two numbers a and b.

From the given info, we can write an expression and solve it:

"one number is 11 more than another number"

a = 11 + b

from this, we know that a > b.

''three times the larger number exceeds four times the smaller number by 4"

3a = 4b + 4

Now we have 2 equations, we can use them to solve using whatever method you want.

a = 11 + b

3a = 4b + 4

I will be using matrices RREF to solve for this.

a - b = 11

3a - 4b = 4

\begin{bmatrix}1 & -1  & 11\\3 & -4 & 4 \end{bmatrix}

\begin{bmatrix}1 & 0  & 40\\0 & 1 & 29 \end{bmatrix}

a = 40

b = 29

6 0
3 years ago
Nêu đặc điểm của tín hiệu PAM rời rạc dạng lưỡng cực NRZ, RZ
zhuklara [117]

Answer:

yes it is certainly good ice cream

4 0
3 years ago
Vector A extends from the origin to a point having polar coordinates (7, 70ᵒ ) and vector B extends from the origin to a point h
yaroslaw [1]

Answer:

13.95

Explanation:

Given :

Vector A polar coordinates = ( 7, 70° )

Vector B polar coordinates = ( 4, 130° )

To find A . B we  will

A ( r , ∅ ) = ( 7, 70 )

A = rcos∅ + rsin∅

therefore ; A  = 2.394i + 6.57j

B ( r , ∅ ) = ( 4, 130° )

B = rcos∅ + rsin∅

therefore ;  B = -2.57i + 3.06j

Hence ; A .B

( 2.394 i + 6.57j ) . ( -2.57 + 3.06j ) = 13.95

8 0
3 years ago
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