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vagabundo [1.1K]
3 years ago
8

If the sum of the daily unpaid balances is $7,812 over a 31-day billing cycle, what is the average daily balance?

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0

Answer:

252

Step-by-step explanation:

Divide 7812 by 31 and we get the average daily answer... Hope this helps!!

You might be interested in
The single equivalent discount rate of the trade discount 6/4/2 is:
Orlov [11]

Answer:

3/1

Step-by-step explanation:

Given the expression 6/4/2, we are to express as a single fraction.

6/4/2

= 6÷4/2

= 6×2/4

= 12/4

= 3/1

Hence the expression as a single fraction is 3/1

4 0
3 years ago
Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
3 years ago
- 3c ( 4x - 2y ) PLESE HELP ASAP I WILL GIVE 5 STARS AND BRAINLIEST
Orlov [11]
12cx+6yc pls mark as brainliest
3 0
3 years ago
Read 2 more answers
Select the correct answer.
zysi [14]

Answer:

A.  -5x = -23

Step-by-step explanation:

First you have to simplify the equation - 4(x - 5) + 8x = 9x - 3

-4x + 20 + 8x = 9x -3

9x - 4x = 20 + 3

5x = 23

=> equivalent to answer A.

8 0
2 years ago
93000000 in standard form
noname [10]
It’s already in standard form: 93,000,000

If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)
3 0
3 years ago
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