Inertia is the resistance offered by a body to the motion whereas momentum is the tendency of a body to continue moving.
OK, this is pretty interesting.
First get out your parameters.
Pressure of gas, P= 1.5×10^5 Pa
Initial volume, V1=0.0002m³
Final volume, V2=0.0006m³
Heat change, ∆H= +32J (it is positive since it was absorbed.)
Now you can solve.
∆U= ∆H—P∆V
∆U=32J—(1.5×10^5×(0.0006—0.0002))
∆U=32J—(1.5×10^5×0.0004)
∆U=32J—(1.5×10^5×4×10^—4)
∆U=32—60
∆U=—28J
That corresponds to option C.
For this problem the figure below shows the representation of a student who pulls on a 20kg box. We know this variables:
Weight of the box = 20kg
Force used by the student to pull on the box = 50N (This is the tension T)
Angle relative to the horizontal = 45 degrees
Aceleration of the box =
The figure also shows the Free-Body diagram, Applying Newton's Second Law we can find the equation for this diagram, related to the x-axis as:
Isolating
:
<span>That is the friction force on the box.</span>
Answer:
Yes it will move and a= 4.19m/s^2
Explanation:
In order for the box to move it needs to overcome the maximum static friction force
Max Static Friction = μFn(normal force)
plug in givens
Max Static friction = 31.9226
Since 36.6>31.9226, the box will move
Mass= Wieght/g which is 45.8/9.8= 4.67kg
Fnet = Fapp-Fk
= 36.6-16.9918
=19.6082
=ma
Solve for a=4.19m/s^2
Answer:
If it has balanced forces, then it is completely still.