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Luden [163]
4 years ago
9

Kai was 200 meters north of the library when he remembered he had to return some books to the library. it took him 200 seconds t

o do the round trip. which best describes kai's roundtrip? his speed was 1 m/s, and his velocity was 0. his speed was 2 m/s, and his velocity was 0. his speed was 1 m/s, and his velocity was 1 m/s north. his speed was 2 m/s, and his velocity was 2 m/s south.

Physics
2 answers:
puteri [66]4 years ago
5 0

Answer: The correct option is 'his speed was 2 m/s, and his velocity was 0.'

Explanation:

In a Round trip the stating point and finishing point are the same.

The distance covered by Kai in 200 seconds = AB+BA =

200 m+200 m = 400 m

Speed of the kai = \frac{distance}{time}=\frac{400 m}{200 s}=2 m/s

Displacement = shortest path covered = AB - BA = 200 m - 200 m =0 m

Velocity of the kai = \frac{displacement}{time}=\frac{0 m}{200 m/s}=0 m/s

Hence, the correct option is 'his speed was 2 m/s, and his velocity was 0.'


Yuliya22 [10]4 years ago
4 0

the answer is B......

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agasfer [191]

Answer:

The charge density in the system is 4.25*10^4C/m

Explanation:

To solve this problem it is necessary to keep in mind the concepts related to current and voltage through the density of electrons in a given area, considering their respective charge.

Our data given correspond to:

r=1*10^{-3}m\\v = 5.2*10^{-4}m/s\\e= 1.6*10^{-19}C

We need to asume here the number of free electrons in a copper conductor, at which is generally of 8.5 *10^{28}m^{-3}

The equation to find the current is

I = VenA

Where

I =Current

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Then replacing,

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I= 22.11a

Now to find the linear charge density, we know that

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And also that the velocity is given in proportion with length and time,

V_d = \frac{l}{t} \rightarrow l = V_d t

The charge density is defined as

\lambda = \frac{Q}{l}\\\lambda = \frac{It}{V_d t}\\\lambda = \frac{I}{V_d}

Replacing our values

\lambda = \frac{22.11}{5.20*10{-4}}

\lambda= 4.25*10^4C/m

Therefore the charge density in the system is 4.25*10^4C/m

5 0
4 years ago
A spring has a period of 1 s when a 0.200 kg mass hung from the end of it. If the mass at the end is changed to 0.100 kg, will t
shutvik [7]

When the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

<u>Explanation:</u>

Given-

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m2 = 0.1 kg

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We know,

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From the equation, we can see that T is directly proportion to the square root of mass, m

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If m1 = 0.2kg , T1 = 1s and m2 = 0.1kg

The T2 would be:

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vaieri [72.5K]

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