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Karo-lina-s [1.5K]
3 years ago
11

3. The center of mass (or center of gravity) of a two-particle system is at the origin. One particle

Physics
1 answer:
nika2105 [10]3 years ago
8 0

Answer:

B) (-2.0 m, 0.0 m)

Explanation:

Given:

Mass of particle 1 is, m_1=2.0\ kg

Mass of particle 2 is, m_2=3.0\ kg

Position of center of mass is, (x_{cm},y_{cm})=(0,0)

Position of particle 1 is, (x_1,y_1)=(3.0\ m,0.0\ m)

Position of particle 2 is, (x_2,y_2)=(?\ m,?\ m)

We know that, the x-coordinate of center of mass of two particles is given as:

x_{cm}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

Plug in the values given.

0=\frac{(2.0\times 3)+(3.0\times x_2)}{2.0+3.0}\\\\0=6+3x_2\\\\3x_2=-6\\\\x_2=\frac{-6}{3}=-2.0\ m

We know that, the y-coordinate of center of mass of two particles is given as:

y_{cm}=\frac{m_1y_1+m_2y_2}{m_1+m_2}

Plug in the values given.

0=\frac{(2.0\times 0)+(3.0\times y_2)}{2.0+3.0}\\\\0=0+3y_2\\\\3y_2=0\\\\y_2=\frac{0}{3}=0.0\ m

Therefore, the position of particle 2 of mass 3.0 kg is  (-2.0 m, 0.0 m).

So, option (B) is correct.

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