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mojhsa [17]
2 years ago
6

How can you relazie a perfect balck body in pratice​

Physics
1 answer:
Mazyrski [523]2 years ago
5 0
A perfect black body can’t be realized
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A cruise started its trip 8:00. Its average speed was 100 km/h.
Aneli [31]

Answer:

120 k/m

Explanation:

5 0
2 years ago
Read 2 more answers
Which planet is to humankind?
Maslowich
Earth. Only. Any other known planets are inapplicable.
3 0
3 years ago
What is temperature? <br>how temperature can be measured​
german

Answer:

Temperature is the kinetic energy of the particles of a substance.

Explanation:

The more kinetic energy a particle has the higher it's temperature. In the case of the atmosphere, which is what we are primarily concerned with in Meteorology, we measure this using a mercury thermometer (in certain situations we use an alcohol thermometer and of course modern times have given us things like dewcells and digital thermometers but we always go back to the mercury thermometer for accuracy).

3 0
1 year ago
To get off a frozen lake, a 70 kg person removes his shoe of mass 0.175 kg and throws it horizontally away from the shore at a v
MakcuM [25]

Answer:

the person will be in the shore at 10.73 minutes after launch the shoe.

Explanation:

For this we will use the law of the lineal momentum.

L_i = L_f

Also,

L = MV

where M is de mass and V the velocity.

replacing,

M_i V_i = M_{fp}V_{fp} + M_{fz}V_{fz}

wher Mi y Vi are the initial mass and velocity, Mfp y Vfp are the final mass and velocity of the person and Mfz y Vfz are the final mass and velocity of the shoe.

so, we will take the direction where be launched the shoe as negative. then:

(70)(0) = (70-0.175)(V_fp) + (0.175)(-3.2m/s)

solving for V_fp,

V_fp = \frac{(3.2)(0.175)}{69.825}

V_fp = 0.008m/s

for know when the person will be in the shore we will use the rule of three as:

1 second -------------- 0.008m

t seconds-------------- 5.15m

solving for t,

t = 5.15m/0.008m

t = 643.75 seconds = 10.73 minutes

 

3 0
3 years ago
A small car with mass m and speed 2v and a large car with mass 2m and speed v both travel the same circular section of an unbank
Alenkasestr [34]

Answer:

(D) F/2

Explanation:

Since the circular section is unbanked, the centripedal acceleration acting on each of the cars is

a_s = \frac{v_s^2}{r} = \frac{(2v)^2}{r} = \frac{4v^2}{r}

a_l = \frac{v_l^2}{r} = \frac{v^2}{r}

Therefore the centripetal force on each car

F_s = m_sa_s = \frac{4mv^2}{r}

F_l = m_la_l = \frac{2mv^2}{r}

Since F_s = 2F_l this means the friction force required to keep the large car on the road is only half of the friction force required to keep the small car on road

So (D) F/2 is the correct answer

5 0
3 years ago
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