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mojhsa [17]
2 years ago
6

How can you relazie a perfect balck body in pratice​

Physics
1 answer:
Mazyrski [523]2 years ago
5 0
A perfect black body can’t be realized
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How to calculate the uncertainty ​
agasfer [191]

Answer:

If you're taking the power of a number with an uncertainty, you multiply the relative uncertainty by the number in the power.

Explanation:

5 0
3 years ago
What is the time period of a simple harmonic oscillator with a mass of 0.3kg and a force constant of 5N/m?
ikadub [295]

Answer: 6N/m

Explanation:

8 0
3 years ago
An air-gap, parallel plate capacitor with area A and gap width d is connected to a battery that maintains the plates at potentia
sergejj [24]

Answer:

The new potential energy decreases by the factor of 2 to the old potential energy.

Explanation:

Capacitance of a parallel plate capacitor is given by the relation :

C = (ε₀A)/d

Here ε₀ is vacuum permittivity, A is area of the capacitor plate and d is the distance between them.

Potential energy of the capacitor, U = \frac{1}{2}CV^{2}

Here V is the potential difference between the plates.

According to the problem, the distance between the plates get double but area remains same. So,

d₁ = 2d

Here d₁ is new distance between the plates.

Hence, new capacitance is :

C₁ = (ε₀A)/d₁ = (ε₀A)/2d = C/2

The capacitor have same potential difference that is V. Hence, the new potential energy is :

U₁ = \frac{1}{2}C_{1} V^{2} = \frac{1}{2}\frac{C}{2} V^{2}

U₁ = U/2

\frac{U_{1} }{U} = \frac{1}{2}

7 0
3 years ago
Saki is ice-staking to the left with velocity of 5 m/s. A steady breeze starts blowing. Causing saki to accelerate leftward at a
Pavlova-9 [17]

Answer:

Final velocity will be equal to 14 m/sec      

Explanation:

We have given initial velocity u = 5 m/sec

Constant acceleration is given a=1.5m/sec^2

Time t = 6 sec

We have to find the final velocity

From first equation of motion v=u+at, here v is final velocity, u is initial velocity , a is acceleration and t is time

So v=5+1.5\times 6=14m/sec

So equal final velocity will be equal to 14 m/sec

4 0
3 years ago
If 500 cal of heat are added to a gas, and the gas expands doing 500 J of work on its surroundings, what is the change in the in
poizon [28]

Answer:

The change in the internal energy of the gas 1,595 J

Explanation:

The first law of thermodynamics establishes that in an isolated system energy is neither created nor destroyed, but undergoes transformations; If mechanical work is applied to a system, its internal energy varies; If the system is not isolated, part of the energy is transformed into heat that can leave or enter the system; and finally an isolated system is an adiabatic system (heat can neither enter nor exit, so no heat transfer takes place.)

This is summarized in the expression:

ΔU= Q - W

where the heat absorbed and the work done by the system on the environment are considered positive.

Taking these considerations into account, in this case:

  • Q= 500 cal= 2,092 J (being 1 cal=4.184 J)
  • W=500 J

Replacing:

ΔU= 2,092 J - 500 J

ΔU= 1,592 J  whose closest answer is 1,595 J

<u><em>The change in the internal energy of the gas 1,595 J </em></u>

6 0
3 years ago
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