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Dimas [21]
4 years ago
7

Define a variable. How does a variable relate to a constant?

Physics
2 answers:
Anettt [7]4 years ago
8 0
By definition, Variable is "(of a quantity) able to assume different numerical values." By this, an example is 4x, as x is an unknown number, but has a value. 
Constants are one constant value, unlike Variables.
Andrei [34K]4 years ago
6 0
<span>In elementary mathematics, a variable is an alphabetic character representing a number, called the value of the variable, which is either arbitrary or not fully specified or unknown</span>
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"what is the horse's average velocity during the first ten seconds of its gallop
vladimir1956 [14]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.

Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)

The unit for velocity (to be used here) is m/s or ms⁻¹

6 0
3 years ago
The formation of lactic acid in human muscle most closely associated with
zavuch27 [327]
The formation of lactic acid in human muscles is closely associated with intense exertion or activity, during which aerobic respiration that uses oxygen to produce energy cannot be able to match the demand of energy by the muscles. The muscles therefore resort to anaerobic respiration for energy where pyruvate becomes a makeshift hydrogen acceptor rather than oxygen as happens in aerobic respiration. Pyruvate accepts a hydrogen from NADH and becomes reduced to lactate or lactic acid while NADH is oxidized to NAD which is crucial in the formation of energy that is then stored in the form of ATP which is used to re-fuel the muscles to keep them going.
8 0
3 years ago
A coil is connected in series with a 19.0 kΩ resistor. An ideal 50.0 V battery is applied across the two devices, and the curren
Gre4nikov [31]

Answer:

inductance of the coil 29.3767  H

Explanation:

given data

resistor R =  19.0 kΩ = 19 × 10³ Ω

potential applied V  = 50.0 V

current I = 2.20 mA  =  2.20 × 10^{-3} A

time t = 2.80 ms = 2.80 × 10^{-3} s

solution

we know for maximum current in circuit that is

current = V ÷ R   .........1

current =  \frac{50}{19\times 10^3}

current = 2.63 × 10^{-3} A

so at time t = 0

t = -\frac{L}{R} ln(1-\frac{I_f}{I_{max}})  

2.80 \times 10^{-3} = -\frac{L}{19\times 10^3} ln(1-\frac{2.20\times 10^{-3}}{2.63\times 10^{-3}}})  

L = 29.3767

3 0
3 years ago
an force of 5N is applied to a 10 kg object over a time of 3s. Determine the impulse applied to the object ​
ddd [48]

Answer:

15Ns

Explanation:

Given parameters:

Mass of the object  = 10kg

Force impact  = 5N

Time of action  = 3s

Unknown:

Impulse applied on the object  = ?

Solution:

Impulse is the force that acts on object within a period of time.

 Mathematically;

             Impulse  = Force x time

Now insert the parameters and solve;

           Impulse  = 5 x 3 = 15Ns

7 0
3 years ago
Andrew pokes a marble, and the marble rolls down a ramp. The marble moves with speed. Which forces are acting on the marble in t
slega [8]
An applied force
gravitational force
friction
4 0
3 years ago
Read 2 more answers
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