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NeTakaya
3 years ago
12

The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion fo

rces. consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type
Chemistry
1 answer:
nlexa [21]3 years ago
3 0
NaCl : In case of Sodium chloride Ionic bonding exists, as sodium is a cation and chloride is an anion. So, these two opposite charged species will attract each other and form ionic bond.

HF : In case of Hydrogen fluoride, Hydrogen bond interactions are found this is because when hydrogen is attached to either Oxygen, Nitrogen or Fluorine atom it gets involve in hydrogen bonding interactions with the neighbor oxygen, nitrogen or fluorine atom (highly electronegative).

HCl :  In Hydrogen chloride dipole dipole interactions exist. A partial positive hydrogen atoms interacts with a partial negative chlorine atom of neighbor molecule.

F2 : As fluorine molecule is neutral and charge less, so it will interact with another fluorine molecule through London dispersion forces.
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Which pair shares the same empirical formula?
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Answer:- 3. CH_3 and C_2H_6

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is C_6H_6 . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and  the empirical formula is CH_2 . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is CH_2 . The C to H ratio for second molecule is 1:4, so the empirical formula is CH_4 . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is CH_3 . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also CH_3 . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is CH_2 . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. CH_3 and C_2H_6

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3 years ago
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In Cis 1,2-dibromomethene, two bromine atoms are present on the same side.

Whereas in Cis 1,2-dibromomethene, two bromine atoms are present on the opposite side and hence, does not have net dipole moment.

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